Answer:
The speed of the water shoot out of the hole is 20 m/s.
(d) is correct option.
Explanation:
Given that,
Height = 20 m
We need to calculate the velocity
Using formula Bernoulli equation
Where,
v₁= initial velocity
v₂=final velocity
h₁=total height
h₂=height of the hole from the base
Put the value into the formula
Hence, The speed of the water shoot out of the hole is 20 m/s.
Answer: Positive.
Explanation:
Given that the ion has a charge of +3.2 x 10^14 C.
When another charge is brought near it, it experiences a repulsive electrostatic force. The other charge brought near the ion must be positive.
This is because the electric field which is a region of space created by the positive ion with a charge of +3.2 x 1014 C have electric lines of force moving outward. Therefore, when another charge is brought near the positive ion, it will either attract or repel depending on the charge of the ion brought into the electric field created by the positive ion.
If the charge on the second ion is also positive, the electric lines of force will be in the same direction as that on the first ion and will their repel. However, if the second ion is negative, the electric field lines are in the opposite direction to that of the first positive ion, thereby creating an attractive electrostatic force in the electric field.
In summary, like charges repel, unlike charges attract.
Answer:
True
Explanation:
The earths gravitational pull keeps it consistent with its orbit.
The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
Know recall that:
We now need to know how much distance is traveled during a minute or 60 seconds:
Finally we divide this result with t=60 seconds:
Where the distance units were named units as the length unit is not specified in this exercise.<span />
2 near the middle
between ultraviolet and infared