Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
The equation solution is y=1, so the two ordered pairs may contain any value of x and a value of 1 for y. (Ex: (-8,1) and (8,1))
Answer:
5. Vertical angle
6. Linear function/linear graph
Brainliest would be appreciated
Answer:
Shorter piece= 4 ft, longer piece= 13 ft
Step-by-step explanation:
If shorter piece is x
Longer pc is 2x + 5
Together they make 17 feet
So x + 2x + 5 = 17
3 x + 5 = 17
3x = 17 - 5 = 12
3x = 12
X = 12/ 3 = 4
So shorter pc is 4 feet
Longer pc is 2 x + 5
= (2 x 4) + 5
= 8 + 5 = 13
