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aleksklad [387]
3 years ago
6

A scientist mixes water (containing no salt) with a solution that contains 35% salt. She wants to obtain 140 ounces of a mixture

that is 15% salt. How many ounces of water and how many ounces of the 35% salt solution should she use?
Mathematics
1 answer:
o-na [289]3 years ago
6 0

Answer:

80 ounces water

60 ounces brine

Step-by-step explanation:

Let x be the amount of water

Let y be the amount of brine 35%

The goal is to have salt weight of 140(0.15) = 21 oz.

21 = 0.35y

y = 60 oz

x = 140 - 60 = 80 oz

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Find variable y<br> : -90=5y-20
NeTakaya

-90= 5y-20

-90+20= 5y-20+20

-70=-5y

-70/-5= -5y/-5

y= 14

7 0
3 years ago
5th grade Pre algebra. Pls help I’m rlly stuck will give brainliest c:
anzhelika [568]

Step-by-step explanation:

so ,

Question 6 :-

5 × (3+4) - 4

first solve the Bracket ......

5 × (7) - 4

after multiplication ......

35 - 4

= 31

so , Answer is 1st one ....

Question 7 :-

8 + 1/2 × (6-2) -1

so , here also solve the Bracket first .....

8 + 1/2 × (4) - 1

after multiplication .....

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4 0
2 years ago
Read 2 more answers
The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.
Olegator [25]

Answer:

<h3>              9, 11, 13, 15</h3>

Step-by-step explanation:

{k - some integer}

2k+1  - the first odd integer (the least)

5(2k+1)  - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3  - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5  - the next odd consecutive integer (third)

2k+5+2 = 2k+7  - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

     - 10k       -10k

-2k + 16 = 8

     -16       - 16    

      -2k = -8  

    ÷(-2)    ÷(-2)  

      k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15  

Check: 9+11+13+15 = 48;  48-3 = 45;  45:5 = 9 = 2k+1

4 0
3 years ago
How do I solve for x
Alchen [17]
Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
a^2+b^2=c^2

Input the information from the diagram into the formula: 
(x)^2+(x+7)^2=(13)^2

Expand each term:
(x)^2+(x+7)^2=(13)^2

x^2+((x+7)(x+7))=169

x^2+(x(x+7)+7(x+7))=169

x^2+x^2+7x+7x+49=169

Combine like terms:
2x^2+14x+49=169

Add -169 to both sides:
(2x^2+14x+49)+(-169)=(169)+(-169)

2x^2+14x-120=0

Factor out the Common Term (2):
2(x^2+7x-60)=0

Factor the Complex Trinomial:
2(x^2-5x+12x-60)=0

2(x(x-5)+12(x-5))=0

2(x-5)(x+12)=0

Set Factors to equal 0:
x-5=0

x=5

or

x+12=0

x=-12

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is: 
\boxed{x=5}

I hope this helped!
-Benjamin

6 0
3 years ago
a 3rd grade teacher has 55 students everyday if those 55 students turned into 100 students how many students would it be.
Tamiku [17]

Answer:

45 because you have to subtract 100-55 which would equal 45

8 0
4 years ago
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