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max2010maxim [7]
1 year ago
5

Difference between compound and element?

Physics
2 answers:
ira [324]1 year ago
8 0

Answer:

Elements are classified as either metals, nonmetals or metalloids. Compounds are classified according to their bonds which can be ionic, molecular or metallic.

Explanation:

deff fn [24]1 year ago
5 0

Answer: Elements are pure substances which are composed of only one type of atom while compounds are substances which are formed by two or more different types of elements that are united chemically in fixed proportions.

Explanation:

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A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (4.3
Ivan

Answer:

B_{m}=1.4333*10^{-8}T

Explanation:

Given data

Ex = Ey = 0

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

To find

The amplitude of the magnetic field component

Solution

The electric field is given by:

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

Where Em=4.3 V/m

The magnitude of magnetic field is given by:

B_{m}=\frac{E_{m}}{c}

Where Em is amplitude of electric field and c is speed of light.

Substitute the given values

So

B_{m}=\frac{4.3V/m}{3.0*10^{8}m/s }\\B_{m}=1.4333*10^{-8}T

7 0
3 years ago
Airbags will deploy no matter from what angle your car is hit.
hram777 [196]
So whats the question?

6 0
3 years ago
Read 2 more answers
Particle A of charge 2.76 10-4 C is at the origin, particle B of charge -6.54 10-4 C is at (4.00 m, 0), and particle C of charge
Vanyuwa [196]

Answer:

a) F_net = 30.47 N ,   θ = 10.6º

b)  Fₓ = 29.95 N

Explanation:

For this exercise we use coulomb's law

          F₁₂ = k k \frac{ q_{1}  \  q_{2} }{ r^{2} }

the direction of the force is on the line between the two charges and the sense is repulsive if the charges are equal and attractive if the charges are different.

As we have several charges, the easiest way to solve the problem is to add the components of the force in each axis, see attached for a diagram of the forces

X axis

        Fₓ = F_{bc x}

Y axis  

       F_{y}Fy = F_{ab} - F_{bc y}

let's find the magnitude of each force

     F_{ab} = 9 10⁹ 2.76 10⁻⁴ 1.02 10⁻⁴ / 3²

      F_{ab} = 2.82 10¹ N

      F_{ab} = 28.2 N

   

      F_{bc} = 9 10⁹ 6.54 10⁻⁴ 1.02 10⁻⁴ / 4²

      F_{bc} = 3.75 10¹  N

       F_{bc} = 37.5 N

let's use trigonometry to decompose this force

      tan θ = y / x

      θ = tan⁻¹ and x

       θ= tan⁻¹ ¾

      θ = 37º

let's break down the force

      sin 37 = F_{bcy} / F_{bc}

      F_{bcy} = F_{bc} sin 37

      F_{bcy} = 37.5 sin 37

      F_{bcy} = 22.57 N

      cos 37 = F_{bcx} /F_{bc}

      F_{bcx} = F_{bc} cos 37

      F_{bcx} = 37.5 cos 37

      F_{bcx} = 29.95 N

let's do the sum to find the net force

X axis

        Fₓ = 29.95 N

Axis y

        Fy = 28.2 -22.57

        Fy = 5.63 N

we can give the result in two ways

a)  F_net = Fₓ i ^ + F_{y} j ^

    F_net = 29.95 i ^ + 5.63 j ^

b) in the form of module and angle

let's use the Pythagorean theorem

    F_net = \sqrt{ F_{x}^2 + F_{y}^2 }

    F_net = √(29.95² + 5.63²)

     F_net = 30.47 N

we use trigonometry for the direction

      tan θ= \frac{ F_{y}  }{  F_{x} }

       

      θ = tan⁻¹ \frac{ F_{y}  }{  F_{x} }

      θ = tan⁻¹ (5.63 / 29.95)

      θ = 10.6º

3 0
3 years ago
A lamp is on a dimmer switch. As you turn the switch from the lowest setting to the highest setting, which statement would best
avanturin [10]

Answer:

D

Explanation:

When something that needs power that you are turning off you will not need power when its off.

8 0
3 years ago
calculate the currrent passing acrooss a bulb if it has a resistane of 15 ohms and a potentinal difference of 6v is applied acro
lawyer [7]

V = IR

6 V = I × 15 Ohms

I = 6 V : 15 Ohms

I = 0,4 A

#LearnWithEXO

4 0
2 years ago
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