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bulgar [2K]
3 years ago
6

Please help answer this

Physics
1 answer:
ddd [48]3 years ago
3 0
I believe the answer is the white dwarf.

The sun will cool then heat up again is my understanding. Hope this helps
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What force to be required to accelerate a car of mass 120 kg from 5 m/s to 25m/s in 2s​
Ira Lisetskai [31]

Answer:1200

Explanation:

F=ma =m(Vf-Vi)/t

F=120(25-5)/2 =1200N

4 0
3 years ago
The upward force on an airplane's wing is thrust.
kompoz [17]

No.  'Thrust' is what most people in aviation call the force
that pushes the aircraft forward. 

The same people generally call the upward force on the wing "lift".

3 0
4 years ago
.A car skid for 290 m. assuming that the car skidded to a stop with a constant
snow_tiger [21]

Answer:

The speed of the car before it began to skid is 47.56 m/s.

Explanation:

We can use kinematics to solve this problem.

We are given three known variables:

  • Δx = 290 m
  • a = -3.90 m/s²
  • v = 0 m/s (final velocity is 0 m/s because the car skids to a stop).

We can use this kinematic equation to <u><em>solve</em></u><em> for the initial velocity</em>, v₀.

  • <u>v² = v₀² + 2aΔx</u>

Substitute the known variables into the equation.

  • (0)² = v₀² + 2(-3.9)(290)
  • 0 = v₀² - 2262
  • 2262 = v₀²
  • <u>v₀ = 47.56 m/s</u>

The speed of the car before it began to skid is 47.46 m/s.

8 0
3 years ago
How should the goals of a beginner differ from someone who is more advanced?
nevsk [136]

Hi!

A beginner is less skilled than someone who is more advanced, and has, in most cases, less experience.

Therefore, if they each set realistic goals for their skill levels, a beginner will have less, adventurous (for lack of a better word) goals because the beginner knows they can achieve less, while an advanced person would set higher goals that are more difficult to achieve, but realistic for themselves.

Hope this helped!

6 0
3 years ago
Air (14.5 lb) undergoes a polytropic process in a closed system from p1 = 80 lbf/in2, υ1 = 4 ft3/lb to a final state where p2 =
Yanka [14]
The energy transfer in terms of work has the equation:

W = mΔ(PV)

To be consistent with units, let's convert them first as follows:

P₁ = 80 lbf/in² * (1 ft/12 in)² = 5/9 lbf/ft²
P₂ = 20 lbf/in² * (1 ft/12 in)² = 5/36 lbf/ft²
V₁ = 4 ft³/lbm
V₂ = 11 ft³/lbm

W = m(P₂V₂ - P₁V₁)
W = (14.5 lbm)[(5/36 lbf/ft²)(4 ft³/lbm) - (5/9 lbf/ft²)(11 lbm/ft³)]
W = -80.556 ft·lbf

In 1 Btu, there is 779 ft·lbf. Thus, work in Btu is:
W = -80.556 ft·lbf(1 Btu/779 ft·lbf)
<em>W = -0.1034 BTU</em>


4 0
3 years ago
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