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MariettaO [177]
3 years ago
12

Which shapes have at least 1 right angle? Choose all that are correct.​

Mathematics
2 answers:
Wittaler [7]3 years ago
6 0

Answer:

The Pink square, Green Rectangle, and the Orange figure

Step-by-step explanation:

The only one I'm not to sure about is the trapezoid, but you can rule out all the others because there is no right angle. Hope this helps!

satela [25.4K]3 years ago
4 0

Answer:The Pink square, Green Rectangle, and the Orange figure :)

Step-by-step explanation:

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PLEASE help me with this equation ​
Brilliant_brown [7]

Answer:

1/25

Step-by-step explanation:

I worked out the equation!

3 0
3 years ago
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Find the measure of the third angle of a triangle given the measures of two angles.<br> 34 and 88
romanna [79]

Answer:

58

Step-by-step explanation:

All three angles of a triangle have to add up to 180. Given this we can do the following problem:

180-34-88 = 58

3 0
3 years ago
Which dot plot is most strongly skewed right?
Y_Kistochka [10]

Answer:where is the photo

Step-by-step explanation:

5 0
3 years ago
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Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
I need help with this ASAP plzzzzz
miss Akunina [59]

Answer:

23. \frac{4\sqrt{3} }{3}

24. \frac{7\sqrt{3}}{3}

25. 6\sqrt{3}

26. \frac{10\sqrt{3} }{3}

27.  14

28. 4\sqrt{3}

Step-by-step explanation:

To solve these i used SOHCAHTOA

sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}

23.

Find the missing side using Tangent

tan(30)=\frac{x}{4}

4*tan(30)=x

\frac{4\sqrt{3} }{3}

24.

Find the missing side using Tangent

tan(30)=\frac{x}{7}

7*tan(30)=x

\frac{7\sqrt{3}}{3}

25.

Find the missing side using Tangent

tan(30)=\frac{x}{18}

18*tan(30)=x

6\sqrt{3}

26.

Find the missing side using Tangent

tan(30)=\frac{x}{10}

10*tan(30)=x

\frac{10\sqrt{3} }{3}

27.

Find the missing side using Tangent

tan(30)=\frac{x}{14\sqrt{3} }

(14\sqrt{3}) *tan(30)=x

14

28.

Find the missing side using Tangent

tan(30)=\frac{x}{12}

12*tan(30)=x

4\sqrt{3}

5 0
3 years ago
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