134.5 grams in 4.5 moles of Li2O (lithium oxide).
Answer:
Gas
Explanation:
Because Crude oil can usually be found in the ground as a liquid and in the air is gas can be kerosene.
Answer: The bond formed between the elements will be ionic bond.
Explanation: We are given two elements having electronic configurations:
Element 1: 
Element 2: 
Element 1 can easily loose 1 electron to attain stable electronic configuration and Element 2 can accept 1 electron to attain stable electronic configuration.
For these elements, there will be a complete transfer of electron from Element 1 to Element 2. Hence, this will form a ionic bond.
From the configuration, Element 1 is Lithium and Element 2 is Fluoride. So, the compound is LiF.
Answer:
The answer to your question is V = 0.32 L
Explanation:
Data
Volume of NH₃ = ?
P = 3.2 atm
T = 23°C
mass of CaH₂ = 2.65 g
Balanced chemical reaction
6Ca + 2NH₃ ⇒ 3CaH₂ + Ca₃N₂
Process
1.- Convert the mass of CaH₂ to moles
-Calculate the molar mass of CaH₂
CaH₂ = 40 + 2 = 42 g
42 g ------------------ 1 mol
2.65 g -------------- x
x = (2.65 x 1)/42
x = 0.063 moles
2.- Calculate the moles of NH₃
2 moles of NH₃ --------------- 3 moles of CaH₂
x --------------- 0.063 moles
x = (0.063 x 2) / 3
x = 0.042 moles of NH₃
3.- Convert the °C to °K
Temperature = 23°C + 273
= 296°K
4.- Calculate the volume of NH₃
-Use the ideal gas law
PV = nRT
-Solve for V
V = nRT / P
-Substitution
V = (0.042)(0.082)(296) / 3.2
-Simplification
V = 1.019 / 3.2
-Result
V = 0.32 L
