Is this molecule polar or nonpolar?

ivolga24 [154]

ANSWER - AEGHNZ (is that right?

3 0

3 years ago

An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu

chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is $4.6656\times 10^{-14}$ .

The density of a proton is $6.278\times 10^{14} g/cm^3$ .

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= $\frac{4}{3}\pi r^3$

Volume of atom = V

$V=\frac{4}{3}\pi r^3$ ..[1]

Diameter of the nucleus ,d' = $9.00\times 10^{-5}\AA$

Radius of the nucleus ,r' = 0.5 d'= $0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA$

Volume of nucleus = V'

$V=\frac{4}{3}\pi r'^3$ ..[2]

Dividing [2] by [1]

$\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}$

$=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}$

$\frac{V'}{V}=4.6656\times 10^{-14}$

The fraction of the volume of the atom that is taken up by the nucleus is $4.6656\times 10^{-14}$ .

Diameter of the proton ,d = $1.72\times 10^{-15} m = 1.72\times 10^{-13} cm$

1 m = 100 cm

Radius of the proton,r = 0.5 d= $0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm$

Volume of the sphere= $\frac{4}{3}\pi r^3$

Volume of atom = V

$V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3$

Mass of proton, m = 1.0073 amu = $1.0073\times 1.66054\times 10^{-24} g$

$1 amu = 1.66054\times 10^{-24} g$

Density of the proton : d

$d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3$

The density of a proton is $6.278\times 10^{14} g/cm^3$ .

5 0

4 years ago

The gas in a balloon occupies 2.25 L at 298 K at what temperature will the balloon expand to 3.50 L

Alenkinab [10]

The temperature that the balloon will expand to 3.50 l is 463.56 K

calculation

by use of Charles law formula

that is V1/T1 = V2/T2 where;

V1 = 2.25 l

T1= 298 k

V2= 3.50 l

T2=?

make T2 the subject of the formula T2 =(V2 xT1) /v1

T2= (3.50 l x 298 K) /2.25 L = 463.56 K

4 0

4 years ago

type of environmental factors such as the presence of a hormone that might affect an organism's phenotype is __________

rosijanka [135]

about the door is locked and I think I have a few questions about the door is locked and I think I have

Explanation:

can you tell me what the door is locked and I think I have a few questions about the door is locked and I think I have a few questions

7 0

3 years ago

Runoffs from a mine have contaminated the groundwater in a location. This might cause health problems among people in the locati

daser333 [38]

Answer:

Collect the runoff in retention ponds lined with protective barriers

Explanation:

The best solution would be to collect the runoff in retention ponds lined with protective barriers.

In order to stop the continuous contamination of the groundwater, it is imperative to cut-off the source of the contaminant which is the run-off. Hence, collecting the runoff in a retention pond lined with protective barriers will ensure that the contaminant's supply is cut-off.

Efforts can then be put in place to decontaminate the already contaminated groundwater.

6 0

3 years ago