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3 years ago

Is this molecule polar or nonpolar?

Chemistry

1 answer:

lutik1710 [3]3 years ago

3 0

The answer is nonpolar

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Is a theory testable, yes or no?

Paraphin [41]

Yes because a theory is based on results and the results are part of the experiment and it being tested. You have to test the experiment and get results so yes a theory is testable.

5 0

3 years ago

You need to make an aqueous solution of 0.243 M iron(III) chloride for an experiment in lab, using a 125 mL volumetric flask. Ho

irakobra [83]

Answer:

5 g

Explanation:

From the question, we have,

Molarity of FeIII solution= 0.245 M

Volume of solution = 125 ml

From

number of moles= concentration × volume

We have;

Number of moles= 0.245 M × 125/1000

Number of moles = 0.031 moles

Molar mass of Fe III = 162.5g/moles

Mass of iron III = number of moles× molar mass = 0.031 × 162.5= 5 g

3 0

4 years ago

Consider the following equilibrium: H2CO3+H2O = H3O+HCO3^-1. What is the correct equilibrium expression?

mylen [45]

Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

<u>Explanation:</u>

Equilibrium expression is denoted by Keq.

Keq is the equilibrium constant that is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

Example -

aA + bB = cC + dD

So, Keq = conc of product/ conc of reactant

$Keq = \frac{[C]^c [D]^d}{[A]^a [B]^b}$

So from the equation, H₂CO₃+H₂O = H₃O+HCO₃⁻¹

$Keq = \frac{[H3O^+]^1 [HCO3^-]^1}{[H2CO3]^1 [H2O]^1}$

The concentration of pure solid and liquid is considered as 1. Therefore, concentration of H2O is 1.

Thus,

$Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

Therefore, Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

4 0

3 years ago

What is the pOH of a solution with [OH-] = 1.4 x 10-13?

lukranit [14]

Answer:

C. 12.85

Explanation:

just did

4 0

3 years ago

Calculate the number of moles in 136g of ammonia

Lesechka [4]

Answer:

Can you be more specific

Explanation:

7 0

3 years ago