Explanation:
Let us assume that the concentration of [
and
is equal to x. Then expression for
for the given reaction is as follows.
![K_{w} = [OH^{-}][H^{+}]](https://tex.z-dn.net/?f=K_%7Bw%7D%20%3D%20%5BOH%5E%7B-%7D%5D%5BH%5E%7B%2B%7D%5D)


Now, we will take square root on both the sides as follows.
M
Thus, we can conclude that the
concentration in neutral water at this temperature is
M.
Answer:
Concentration ammonium is 0.036 g/mL
Explanation:
Stock solution has concentration of 0.108g/mL. Take 10mL stock solution and add 50 mL of water meaning it has 1,08g/60mL. Ammonium sulfate has 2 molecules of cation ammonium cation. So, (1,08g/60mL.)*2=0.036 g/mL
Answer:
Empirical and molecular formulas are the same, C₅H₁₀O₂.
Explanation:
Hello!
In this case, when determining the empirical and molecular formulas of organic compounds via combustion analysis, we first need to compute the moles of carbon and hydrogen via the yielded mass of carbon dioxide and water:

Next, we need to compute the mass of oxygen by subtracting the mass of carbon and hydrogen to the mass of the sample of the compound:

And consequently the moles:

Now, we need to divide the moles of each atom by the fewest moles, it in this case, those of oxygen to obtain the subscripts in the empirical formula:

Thus, the empirical formula, taken the nearest whole number is:

Now, if we divide the molar mass of the molecular formula (102.1 g/mol) by that of the empirical formula (102.1 g/mol) we infer they are both the same.
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Answer:
4Cr + 3O2 —> 2Cr2O3
Explanation:
Information from the question include:
Chromium + oxygen -> chromium(III) oxide
From the word equation given above, the equation can be written as follow:
Cr + O2 —> Cr2O3
The equation can be balance by doing the following:
There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of Cr2O3 and 3 in front of O2 as shown below:
Cr + 3O2 —> 2Cr2O3
Now, we have 4 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 4 in front of Cr as shown below:
4Cr + 3O2 —> 2Cr2O3
Now the equation is balanced
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