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Travka [436]
3 years ago
9

Subject:Mathematics ​

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0
The vertex
Blah blah blah 20 characters longggggg
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Write equation in standard form:<br> 1.y=3/4x+5<br><br><br> 2.y+4=1/3(x+6)
Gwar [14]
1. 3x - 4y = 20

2. x - 3y = -6
5 0
3 years ago
How do I solve x in a triangle
Sindrei [870]

All three sides always add up to 360 so add the given measures and subtract it from 360 and that would give you your answer.

3 0
3 years ago
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Find the GCF of 56 and 40. <br>A.2<br>B.4<br>C.8<br>D.280
statuscvo [17]
<span><span>56:   222 7</span><span>40:   2225 </span><span>GCF:   222  </span></span>

The Greates Common Factor (GCF) is:   2 x 2 x 2 = 8

8 0
3 years ago
A circle is centered on point B, Points A, C and D lie on its circumference. if ABC measures 46 degrees, what does ADC measures?
den301095 [7]
Answer: 23 degrees

---------------------------------------
---------------------------------------

Explanation:

Using the inscribed angle theorem we can connect the central angle ABC and the inscribed angle ADC. The reason why is because they both cut off the minor arc AC

Angle ABC is given to be 46 degrees, the formula we use is shown below

central angle = 2*(inscribed angle)
angle ABC = 2*(angle ADC)
46 = 2*(angle ADC)
46/2 = 2*(angle ADC)/2 ... divide both sides by 2
23 = angle ADC
angle ADC = 23 degrees

5 0
2 years ago
How do you graph -1/5x-1 and 4/5x-6
kakasveta [241]

Answer:

The points for the given to linear equations is (5 , - 2) and (5 , - 1)

The points is plotted on the graph shown .

Step-by-step explanation:

Given as :

The two linear equation are

y = \dfrac{-1}{5}x - 1                  ...........1

y = \dfrac{4}{5}x - 6                  ...........2

Now, Solving both the linear equations

Put the value of y from eq 2 into eq 1

I.e  \dfrac{4}{5}x - 6 = \dfrac{-1}{5}x - 1

Or, \dfrac{4}{5}x + \dfrac{1}{5}x  = 6 - 1

Or,  \dfrac{4 + 1}{5}x = 5

or, \dfrac{5}{5}x = 5

∴ x = 5

Now, Put the value of x in eq 1

So, y = \dfrac{-1}{5}x - 1      

Or, y = \dfrac{-1}{5}× 5 - 1              

or,  y = \dfrac{-5}{5} - 1

Or, y = - 1 - 1

I.e y = -2

So, For x = 5 , y = - 2

Point is (x_1 , y_1) = (5 , - 2)

Again , put the value of x in eq 2

So, y = \dfrac{4}{5}x - 6

Or, y = \dfrac{4}{5}× 5 - 6

Or, y = \frac{4\times 5}{5} - 6

Or, y = 4 - 6

I.e y = - 2

So, For x = 5 , y = - 2

Point is (x_2 , y_2) = (5 , - 2)

Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)

The points is plotted on the graph shown . Answer

5 0
3 years ago
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