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zubka84 [21]
2 years ago
8

Tính (1,5)4; ((-2)/3)3; (√3)5.

Mathematics
1 answer:
polet [3.4K]2 years ago
8 0

Step-by-step explanation:

câu trả lời là trong bức ảnh trên

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16 = 9 + m how do I solve this?
Degger [83]

Answer:

16=9+m m=7

Step-by-step explanation:

m=7 makes the equation true

3 0
4 years ago
What is the equation of the line in slope-intercept form?ASAP!!! Please
bezimeni [28]
We use y=mx+c we know that c= 4 A’s this is the y intercept . Next we need to work out the gradient(m). For every two squares along we go three squares up. This means are gradient is 1.5. Finally we input are values into the equation y=1.5x+4
4 0
3 years ago
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What is 4(a5+7)+6(b7-5)
Andrej [43]
4a5+28+6b7-30
4a5+6b7-2<—- this is a to the power of 5 , b to the power of 7
(Is that 5a or a to the power of 5 )
20a+28+42b-30
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4 0
3 years ago
Julius is buying beverages for brunch. He needs to buy a total of 5
xeze [42]
Well, he only needs 5 gallons of beverages. Because he buys two containers of each, however, that means he bought 320 gallons total (I would say). How I got my answer:

There are 8 pints in a gallon (8 x 2)
There are 4 quarts in a gallon (4 x 2)
There are 16 cups in a gallon (16 x 2)
There are 128 ounces in a gallon (128 x 2)

With that being said, we can add these to find the total amount of gallons of beverages Julius bought. 16 + 8 + 8 + 32 + 256 = 320.

Hopefully this helps!
7 0
2 years ago
A truck weighing 150kN and travelling at 2m/sec impacts with a buffer
FrozenT [24]

The maximum compression of the spring is 0.276 m

Step-by-step explanation:

First of all, we calculate the spring  constant of the spring, by using Hooke's law:

F=kx

where

F = 10 kN = 10,000 N is the force applied

x = 1.25 cm = 0.0125 m is the corresponding compression of the spring

k is the spring constant

Solving for k,

k=\frac{F}{x}=\frac{10,000}{0.0125}=8\cdot 10^5 N/m

When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write

\frac{1}{2}mv^2=\frac{1}{2}kx^2 (1)

where

m is the mass of the truck

v = 2 m/s is the initial speed of the truck

k=8\cdot 10^5 N/m is the spring constant

x is the compression of the spring

The mass of the truck can be found from its weight:

m=\frac{W}{g}=\frac{150,000 N}{9.81 N/kg}=15,290 kg

So now we can re-arrange eq.(1) to find the compression, x:

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(15,290)(2)^2}{8\cdot 10^5}}=0.276 m

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

6 0
3 years ago
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