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3 years ago

11

Jurado picked 40 bags of apples on Monday and sold them at his fruit stand for $3:45 each. The following week he picked and sold

26 bags. How much money did Judas earn in this first week??

1 answer:

tekilochka [14]3 years ago

4 0

I'm pretty sure that would be $89.70!

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Ms. taylor bought a water tube to pull behind her boat. the tube cost $87.00 and 9% sales tax was added at the register. ms.tayl

zhuklara [117]

Work out 9% of $87.00 then add theat to the $87.00 that will be the total cost. find how much cash she gave the cashier and then minus the total cost from that to find the change she got.

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4 years ago

For what values of does the equation (2 + 1)^2 + 2 = 10 − 6 have two real and equal roots?

adelina 88 [10]

Answer:

(2 + 1)^2 + 2 = 10 - 6

Falso

Step-by-step explanation:

The left side

11

does not equal to the right side

4

, which means that the given statement is false.

False

4 0

3 years ago

N-4n=-9+6n<br> A) (-9)<br> B) (1)<br> C) (All real numbers. }<br> D) (14)

xeze [42]

The answer is B I hope you get it.

6 0

3 years ago

A number decreased by 23% equals 123

Elden [556K]

Answer:

100 is inital value of that decrease

7 0

3 years ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago