Answer:
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Step-by-step explanation:
Given that, the rate R(t) at which cars enter the highway is given the formula
The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.
![=[100(t-0.0001\frac{t^3}{3})]_0^{30}](https://tex.z-dn.net/?f=%3D%5B100%28t-0.0001%5Cfrac%7Bt%5E3%7D%7B3%7D%29%5D_0%5E%7B30%7D)
![=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]](https://tex.z-dn.net/?f=%3D100%5B%2830-0.0001%5Cfrac%7B30%5E3%7D%7B3%7D%29-%280-0.0001%5Cfrac%7B0%5E3%7D%7B3%7D%29%5D)
=2901
The average rate of car is 
=97
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Answer: I really dont know sorry
Step-by-step explanation:
Answer:
y*5+3=38
Step-by-step explanation:
A real world example could be:
Consider x is time in minutes
Consider y is the amount of fish food required in grams
The equation could then represent how much food (in grams) that a fish needs to be fed x minutes after it was previously fed.
Answer:
$9.50h, $(9.50h +2.20rh)
Step-by-step explanation:
Every hour ----- $9.50
h hours ----- h ×$9.50
Amount of money Mr Smith earns in h hours
= $9.50h
If he fixes a watch per hour, additional income= $2.20h
If he fixes r watches per hour, additional income= $2.20rh
Total income
= $(9.50h +2.20rh)
