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patriot [66]
3 years ago
14

Plisssss you can help me pliss

Physics
1 answer:
Nesterboy [21]3 years ago
6 0
For the first one it’s the guh sound
And the second one it’s the kuh sound
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How many moles of MgCl2 are there in 329 g of the compound?<br><br> Your Answer:
Nookie1986 [14]

Answer:3.46

Explanation:

mass=329

molar mass=71

no. of moles=329/71

=3.46

6 0
3 years ago
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Calculate the mass of an object that has a momentum of 100kg x m/sec and velocity of 4 m/sec
lidiya [134]
P= mv

where p is momentum
m is mass
v is velocity

so it's given p= 100kgm/sec
v= 4m/s

so putting in the formula

100= m × 4

m = 25kg
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3 years ago
HELPPPP QUESTION IS ABOVE
anygoal [31]

Answer:

discount rate

Explanation:

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3 years ago
Light refracts when traveling from air into glass because light
ella [17]

Answer:

Speed of light changes

Explanation:

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3 0
3 years ago
One afternoon, a couple walks three-fourths of the way around a circular lake, the radius of which is 2.51 km. they start at the
Marysya12 [62]
(a) Since the lake has a circular shape, the distance they traveled is exactly 3/4 of a circumference. The radius of the lake is 2.51 km, and the circumference is given by 2\pi r, therefore the distance covered is
d= \frac{3}{4} (2 \pi r) = \frac{3}{2} \pi (2.51 km)=11.82 km

(b) We can consider the lake to be on a xy-plane with the origin of the axes being at the center of the lake. In this system of coordinates, the starting point of the motion is at the west side of the lake, so at coordinates (-2.51 km,0). The final point is after 3/4 of circumference, therefore at the north side, at coordinates (0, 2.51 km).
So we can calculate the magnitude of the displacement as
d= \sqrt{(x_f-x_i)^2+(y_f-y_i)^2} = \sqrt{(0-(-2.51))^2+(2.51-0)^2}=
=3.55 km

(c) Considering only the initial and final point of the motion, the couple moved 2.51 km north (on the x-axis) and 2.51 km east (on the y-axis). Therefore, we can calculate the angle of the displacement with respect to the east direction:
\tan \alpha =  \frac{\Delta y}{\Delta x} = \frac{2.51 km}{2.51 km}=1
from which
\alpha=45^{\circ}
3 0
3 years ago
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