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Scorpion4ik [409]
3 years ago
6

HELP ME PLEASEEE!

Mathematics
1 answer:
Molodets [167]3 years ago
5 0
The answer is -1,3 ok ok
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Toni rides the Ferris wheel shown for 15 revolutions. A photo of a Ferris wheel has the diameter labeled fifty-six feet. Questio
NARA [144]

Answer:

a. 176 feet b. 2640 feet

Step-by-step explanation:

a. Since the diameter of the Ferris wheel is D = 56 feet, the distance Toni travels in one revolution is the circumference of the Ferris wheel, C = πD.

So C = 22/7 × 56 ft = 22 × 8 ft = 176 feet

b. The distance traveled in 15 revolutions is thus D' = 15 × distance of one revolution = 15 × 176 = 2640 feet

5 0
3 years ago
I will give you a Brainly crown if it is right. Will you help me
Lostsunrise [7]

Answer:

-12

Step-by-step explanation:

4 time 3 is 12

since he owes her its negative, so it is -12

3 0
3 years ago
Read 2 more answers
1. x=1/(root3-root2). find rootx-(1/rootx) 2. if x=[root(a+2b)+root(a-2b)]/[root(a+2b)-root(a-2b]. show that bx^2-ax+b=0
timofeeve [1]
1. x = 1/ ( \sqrt{3} -  \sqrt{2)} = \sqrt{3}+  \sqrt{2};
 ( \sqrt{x} -1/ \sqrt{x} )^{2} = x + 1/x - 2 = = 
6 0
3 years ago
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What’s the value of 27.43? Write answer in a fraction
Nezavi [6.7K]

Answer:

As an improper fraction: 27 \frac{43}{100}

As a mixed fraction: \frac{2743}{100}

Step-by-step explanation:

Any number could be expressed as a fraction 27 is \frac{27}{1} and since 0.43 is forty-three hundredths we can express it as \frac{43}{100}.

To find the answer as a mixed fraction we have to put the whole number in the beginning and the fraction in the end. 27 \frac{43}{100}

As an improper fraction we have to add 27 / 1 + 43/100 = \frac{2743}{100}

4 0
3 years ago
Read 2 more answers
Solve the system of equations.<br> <img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7By%3D220x-160%7D%20%5Catop%20%7By%3
Leni [432]

\begin{cases} y=220x-160\\ y=20x^2-400 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{\stackrel{\textit{\Large y}}{220x-160}~~ = ~~20x^2-400} \\\\\\ -160=20x^2-220x-400\implies 0=20x^2-220x-240 \\\\\\ 0=20(x^2-11x-12)\implies 0=x^2-11x-12 \\\\\\ 0=(x-12)(x+1)\implies x= \begin{cases} 12\\ -1 \end{cases}

\dotfill\\\\ x=12\qquad \qquad \stackrel{\textit{substituting on the 1st equation}}{y=220(12)-160}\implies y=2480 \\\\\\ x=-1\qquad \qquad \stackrel{\textit{substituting on the 1st equation}}{y=220(-1)-160}\implies y=-380 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (12~~,~~2480)\qquad (-1~~,~~-380)~\hfill

4 0
3 years ago
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