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3 years ago

9

Helppppp!!!!!! Plsss

1 answer:

PtichkaEL [24]3 years ago

6 0

Answer:

A!

Step-by-step explanation:

open circle = the number it's on isn't an answer

the arrow is pointing left, the negative side so it's less than :)

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14) At a school 5/8 of the teachers are male

Lady bird [3.3K]

If 5/8 of the teachers are males, there are 45 male teachers.

Subtract this value from 72 (i.e., find 3/8 of 72), and you will find that there are 27 female teachers.

8 0

3 years ago

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Determine if the two triangle are congruent. If they are, state how?

Murrr4er [49]

Answer:

The triangles are congruent by SAS.

Step-by-step explanation:

The triangle have two congruent sides because it is given. The congruent angle is the angle at which they connect, these two angles are congruent because they are vertical angles.

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3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

F(-2)=-2²+3(-2)-2 find f(-2)

olga_2 [115]

Answer:

F(-2)=-2²+3(-2)-2=4+-6×-2=4+12=16

5 0

3 years ago

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The farmers wife baked 9 pies on Monday and 5 on Tuesday. How many more pies did she bake on Monday?

insens350 [35]

Answer:

4

Step-by-step explanation:

9 - 5 = 4

6 0

3 years ago