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Alenkinab [10]
2 years ago
12

Tan 2A + sin 2A=4 tan A/(1 - tan4 A)​

Mathematics
1 answer:
stich3 [128]2 years ago
3 0

Answer:

when \:  \\  \tan(2x)  =   \frac{2 \tan(x) }{1 -  {( \tan(x)) }^{2} }  \:  \: and \\  \sin(2x)  =  \frac{2 \tan(x) }{1 +  {( \tan(x)) }^{2} }  \\ then \\  \sin(2x)  +  \tan(2x)  =  \frac{2 \tan(x) }{1 -  {( \tan(x)) }^{2} }  +  \frac{2 \tan(x) }{1 +  {( \tan(x)) }^{2} }  \\  =  \frac{2 \tan(x)(1 +  {( \tan(x)) }^{2}  + 2 \tan(x) (1 -  {( \tan(x)) }^{2}  }{(1 +  {( \ \tan(x))  }^{2}(1 -  {( \tan(x)) }^{2}  }  \\  =  \frac{2 \tan(x) \times 2 }{1 -  {( \tan(x) }^{4} }  \\  =  \frac{4 \tan(x) }{1 -  {( \tan( \times ) )}^{4} }

Step-by-step explanation:

If you need any explanation. I can do it, my friend. you can communicate with me to that or any thing do you need in math

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