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vaieri [72.5K]
4 years ago
14

Which of the following has no electrons? Use a periodic table. Question 1 options: H He H– He 2+ Save

Chemistry
1 answer:
Elodia [21]4 years ago
6 0

An electron is a negatively charged subatomic particle present in the space outside the nucleus of an atom. The loss of electron from an atom results in the formation of cation whereas gaining of electron by an atom results in the formation of anion. The cation possesses positive charge due to loss of electron and anion possesses negative charge due to gain of electron.

The neutral atom has no charge on it.

For given atomic symbols:

  • H

The atomic number of hydrogen is 1 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in H is 1.

  • He

The atomic number of helium is 2 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in He is 2.

  • H^{-}

The atomic number of hydrogen is 1 and the given symbol has a negative charge that represents a gain of electron. So, the number of electrons in H^{-} is 2.

  • He^{2+}

The atomic number of helium is 2 and the given symbol has two positive charge that represents loss of two electrons. So, the number of electrons in He^{2+} is 0.

Hence, He^{2+} has no electrons.

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Answer: Isotope A was measured at day 24, Isotope B was measured at day 6, and Isotope C was measured at day 10.

Explanation:

The half-life time is defined as the time needed for the radioactive isotope to decay to the half of its initial concentration.

  • Isotope A: its starting weight 95 g and its ending measured weight is 5.9.

95 → 47.5 (half-life 1) → 23.75 (half-life 2) → 11.875 (half-life 3) → 5.9 (half-life 4).

It needs 4 half-lives to decay from 95 to 5.9.

half-life time of isotope A = 6 days.

the time taken to measure isotope A = (4 x 6 days) = 24 days.

  • Isotope B: its starting weight 20 g and its ending measured weight is 2.5.

20 → 10 (half-life 1) → 5 (half-life 2) → 2.5 (half-life 3).

It needs 3 half-lives to decay from 20 to 2.5.

half-life time of isotope B = 2 days.

the time taken to measure isotope B = (3 x 2 days) = 6 days.

  • Isotope C: its starting weight 45 g and its ending measured weight is 22.5.

45 → 22.5 (half-life 1)

It needs 1 half-life to decay from 45 to 22.5.

half-life time of isotope C = 10 days.

the time taken to measure isotope C = (1 x 10 days) = 10 days.

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What number and types of atoms occur in a formula unit of<br> Ca(NO3),?
pav-90 [236]

Answer:

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Write the equation of the mirror line for the segment with endpoints (5, 4) and (-1, -1).
charle [14.2K]

Answer:

Explanation:

{\displaystyle {}^{n}x}{}^{n}x, for n = 2, 3, 4, …, showing convergence to the infinitely iterated exponential between the two dots

In mathematics, tetration (or hyper-4) is an operation based on iterated, or repeated, exponentiation. It is the next hyperoperation after exponentiation, but before pentation. The word was coined by Reuben Louis Goodstein from tetra- (four) and iteration.

Under the definition as repeated exponentiation, the notation {\displaystyle {^{n}a}}{\displaystyle {^{n}a}} means {\displaystyle {a^{a^{\cdot ^{\cdot ^{a}}}}}}{\displaystyle {a^{a^{\cdot ^{\cdot ^{a}}}}}}, where n copies of a are iterated via exponentiation, right-to-left, I.e. the application of exponentiation {\displaystyle n-1}n-1 times. n is called the "height" of the function, while a is called the "base," analogous to exponentiation. It would be read as "the nth tetration of a".

Tetration is also defined recursively as

{\displaystyle {^{n}a}:={\begin{cases}1&{\text{if }}n=0\\a^{\left(^{(n-1)}a\right)}&{\text{if }}n>0\end{cases}}}{\displaystyle {^{n}a}:={\begin{cases}1&{\text{if }}n=0\\a^{\left(^{(n-1)}a\right)}&{\text{if }}n>0\end{cases}}},

allowing for attempts to extend tetration to non-natural numbers suc

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Which of the following describes when he is transferred as a form of light
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Answer:

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HVL is that amount of material that will reduce the original intensity to half of its value. One HVL will reduce the 100 R/minute to 50 R/minute, a second HVL will reduce the 50 R/minute to 25 R/minute

Explanation:

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Which chemistry studies non carbon based structures?
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Answer:

Inorganic chemistry

Explanation:

Meaning: Inorganic chemistry studies substances that do not contain carbon; therefore, it studies non carbon based structure.

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