Answer:
In elxplaination
Explanation:
Phase Change:s Evaporation, Condensation, Freezing, Melting, Sublimation & Deposition.
Calcium carbonate is most likely to dissolve in water with:
e. Lots of Carbon dioxide and colder temperature.
Explanation:
- Calcium carbonate is very sparingly soluble in water. However, it has been observed to dissolve in cold water with higher concentration of Carbon dioxide.
- The reason behind the observation is the formation of Calcium bicarbonate which is soluble in water.
- Higher concentration of Carbon dioxide in water turns it acidic. When this acidic water reacts with calcium carbonate it forms Calcium bicarbonate which is soluble in water.
- So,Calcium carbonate is most likely to dissolve in water with lots of Carbon dioxide and colder temperature.
Answer:
The correct answer is 0.165 g NaCl.
Explanation:
The following is the precipitation reaction taking place between sodium chloride and silver nitrate:
NaCl (aq) + AgNO₂ (aq) ⇒ NaNO₃ (aq) + AgCl (s)
The complete ionic reaction of the reaction will be,
Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ ⇒ AgCl (s) + Na⁺ + NO₃⁻
Hence, the net ionic equation for the mentioned reaction is:
Ag⁺ (aq) + Cl⁻ (aq) ⇒ AgCl (s)
Thus, it can be witnessed that one mole of chloride ion is needed so that one mole of Ag⁺ ion get neutralized. There is a need to find the moles of silver ions present in the solution of AgNO₃ and then transform these moles to the moles of chloride ion. Ultimately, these moles can be converted to the concentration of sodium chloride needed.
The no. of moles of silver ions found in silver nitrate solution is,
(2.50 × 10² mL) × (0.0113 mol Ag⁺/1000 ml solution) = 2.83 × 10⁻³mol Ag⁺
Now the moles of chloride ions needed to precipitate the silver ions is,
(2.83 × 10⁻³ mol Ag⁺ ) × (1 mol Cl⁻/1 mol Ag⁺) = 2.825 × 10⁻³mol Cl⁻
The mass of sodium chloride needed for precipitating the silver ions will be,
mass of NaCl = (2.83 × 10⁻³ mol Cl⁻) × (1 mol NaCl / 1 mol Cl⁻) × (58.44 grams / 1 mol NaCl)
= 0.165 gram NaCl.
The answer is it tends to be more negative down a group. This is because as you go down the periodic table, the elements have more electron shells in their atoms. This makes the outermost shells less attracted to the nucleus due to their greater distances from the nucleus. Therefore, these shells are less likely to attract electrons (hence lower electron affinity) and are even more likely to lose electrons from their outer electron orbits.