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goblinko [34]
3 years ago
11

PLLLZZZZZZZZZZZZZZZ HELPPPPPP MEEEEEEEEEEEE THHHXXX

Chemistry
1 answer:
Olegator [25]3 years ago
3 0
The awnser to your question would be B
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D) hydrogen and sulfur<br> Formed
mr Goodwill [35]

Answer:

At high temperatures or in the presence of catalysts, sulfur dioxide reacts with hydrogen sulfide to form elemental sulfur and water. This reaction is exploited in the Claus process, an important industrial method to dispose of hydrogen sulfide.

3 0
3 years ago
Need help with number 17 pleasee
kap26 [50]

Answer:

I'm pretty sure the answer is D, I could be wrong tho

3 0
3 years ago
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sam records the mass of his evaporating dish as 8.365 g. he records the mass of the evaporating dish and the sample of hydrate a
guapka [62]

0.2701 moles of water were evaporated from the sample by the heating process

Mass of evaporating dish = 8.365 g

mass of dish + hydrate = 18.597 g

mass of hydrate =  (mass of dish + hydrate) - mass of dish

hydrate = 18.597 - 8.365 = 10.232 g

Mass of dehydrated material = (mass of dish + dehydrate ) - mass of dish

dehydrated material = 18.735 - 8.365 = 5.37 g

Mass of water evaporated = hydrate - dehydrate

mass of water = 10.232 - 5.37 = 4.862 g

Molar mass of water  = 18 gm/mol

no. of moles of water evaporated = mass / molecular mass

moles = 4.862/18 = 0.2701 moles

To learn more about mole click here:

brainly.com/question/29367909

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7 0
1 year ago
For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [
sveta [45]

Explanation:

The given data is as follows.

     E^{o} = 0.483,     [Co^{3+}] = 0.173 M,

     [Co^{2+}] = 0.433 M,     [Cl^{-}] = 0.306 M,

     P_{Cl_{2}} = 9.0 atm

According to the ideal gas equation, PV = nRT

or,             P = \frac{n}{V}RT    

Also, we know that

                Density = \frac{mass}{volume}

So,         P = MRT

and,          M = \frac{P}{RT}

                    = \frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}

                    = \frac{9.0}{24.436}

                    = 0.368 mol/L

Now, we will calculate the cell potential as follows.

          E = E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}

             = 0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}

             = 0.483 - 0.02955 log \frac{0.0689}{0.0162}

             = 0.483 - 0.02955 \times 0.628

             =  0.483 - 0.0185

             = 0.4645 V

Thus, we can conclude that the cell potential of given cell at 25^{o}C is 0.4645 V.

4 0
4 years ago
3. What are vaccines? Are there different types?​
Inga [223]

Answer:Four types of vaccines are currently available: Live virus vaccines use the weakened (attenuated) form of the virus. The measles, mumps, and rubella (MMR) vaccine and the varicella (chickenpox) vaccine are examples

4 0
4 years ago
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