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3 years ago

Choose the function whose graph is given by:

Mathematics

1 answer:

Inessa [10]3 years ago

7 0

B. Y=2sec(2x)

This is cuz the others don’t match the graph and only this one does.

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Write an equation of a parabola that passes through the point (2,4) with vertex (-1,-1) in vertex form.

quester [9]

An applicable equation of a vertical parabola in vertex form is:

y-k = a(x-h)^2

Let x=2, y=4, h=-1 and k=-1, where (h,k) is the vertex. Then,

4-(-1) = a(2-[-1])^2, which becomes 5 = a(9). Therefore, a = 5/9, and the
equation of the parabola is

y+1 = (5/9)(x+1)

8 0

3 years ago

PLEASE HELP!

Degger [83]

Answer:

Perimeter = 21.58 units

Step-by-step explanation:

Perimeter of a polygon = Sum of measures of all sides of the polygon

Perimeter of the quadrilateral LEAP = PL + AE + EL + LP

= 4.47 + 4.47 + 6.32 + 6.32

= 21.58 units

[If the distances between two point are not given, use the formula to calculate the distance between two points $(x_1, y_1)$ and $(x_2,y_2)$

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ ]

7 0

3 years ago

The tables show some input and output values:

Radda [10]

A because one input can have only one output

3 0

3 years ago

Read 2 more answers

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

3 years ago

the minute hand of a clock is 5 inches long. what is the area of the circle, in square inches, created in a hand sweep in an hou

ira [324]

Solve the area of the whole circle since in an hour, the minute hand covers the whole clock
assuming that the minute hand reaches all the way out to the edge of the clock

the minute hand is the radius
area=pi times r^2
r=5
5^2=25
area=pi times 25
area=25pi

aprox pi=3.14
25 times 2.14=78.5

area=78.5 in^2

6 0

3 years ago