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aksik [14]
3 years ago
10

Need help!!!! For school

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

Your answer is.....

A,   It is multiplicative

Mark it as brainlist answer . follow me for more answer.

Step-by-step explanation:

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0.304x10 to the fifth power
trasher [3.6K]
1) 0.304x10=3.04
2) 3.04^5=3.04x3.04x3.04x3.04x3.04
3) 3.04^5=259.367

Hope I helped,
-CSX :)
8 0
3 years ago
Read 2 more answers
Can this visual be described with a linear, exponential, or neither
Pachacha [2.7K]

Answer: Linear

Step-by-step explanation:

Seven squares are added each time, so if the amounts of squares were to be charted on a graph, the line would be linear, making the visual linear.

4 0
3 years ago
1. Given line segment RB and on it is point C, if RB = 45 and CB = 3x - 12 and RC = 2x + 9, what is the value of x?
marshall27 [118]

Answer:

Step-by-step explanation:

1). If a point C is lying on a line segment RB,

   Then RB = RC + CB

   Since, RB = 45, CB = 3x - 12 and RC = 2x + 9

   45 = (2x + 9) + (3x - 12)

   45 = (2x + 3x) - 3

   48 = 5x

   x = \frac{48}{5}

   x = 9.6

2). Since, RC = 2x + 9

    RC = 2(9.6) + 9

          = 19.2 + 9

          = 28.2 units

3). Distance between the two points (x_1,y_1) and (x_2,y_2) is given by the formula,

  d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

  Distance between the points A(2, -2) and D(-2, 2) will be,

 AD=\sqrt{(2+2)^2+(-2-2)^2}  

         = \sqrt{16+16}

         = 4\sqrt{2}  

         = 5.657

         ≈ 5.66 units

7 0
3 years ago
Prove using the notion of without loss of generality that 5x 5y is an odd integer when x and y are integers of opposite parity.
kap26 [50]
The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
6 0
3 years ago
What is 4,173 in exponential form
Ket [755]

Step-by-step explanation:

\underline{\begin{array}{c|c|c|c}4&1&7&3\end{array}}\\\begin{array}{c|c|c|c}4&0&0&0\\&1&0&0\\&&7&0\\&&&3\end{array}

4,173 = 4,000 + 100 + 70 + 3\\\\=4\times1,000+1\times100+7\times10+3\times1\\\\=4\times10^3+1\times10^2+7\times10^1+3\times10^0

7 0
3 years ago
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