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Vsevolod [243]
3 years ago
13

I need this please help me

Mathematics
1 answer:
rewona [7]3 years ago
4 0
Function a has a rate of change of 2 and function b has a rate of change of .75. So function a has a greater rate of change.
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In parallelogram ABCD,AB^4+AD^2+AB^2*AD^2=AC^2*BD^2.If angle ABC=x,find the product of all possible values of x
almond37 [142]

Answer:

Hello,

Step-by-step explanation:

AB=DC=b, AD=BC=a

p=BD, q=AC

angle ABC=x

AB^4+AD^4+AB^2*AD^2=AC^2*BD^2\\\\b^4+a^4+b^2a^2=(a^2+b^2+2abcos(X))(a^2+b^2-2abcos(X)\\\\(a^2+b^2+2a^2b^2)-a^2b^2=((a^2+b^2)^2-4a^2b^2*cos^2(X))\\\\\\4a^2b^2cos^2(X)=a^2b^2\\\\\\cos^2(X)=\dfrac{1}{4} \\\\(cos(X)-\dfrac{1}{2} )(cos(X)+\dfrac{1}{2} )=0\\cos(x)=\frac{1}{2} \ or\ cos(X)=\dfrac{-1}{2} \\\\\\X=60^o =\dfrac{\pi}{3} rad \ or \ X=120^o=\dfrac{4\pi}{3} rad\\\\\\\\Product=\dfrac{\pi}{3}*\dfrac{4\pi}{3} =\boxed{\dfrac{4\pi^2}{9}}\\

8 0
3 years ago
Evaluate (-12)(-2) 2 576 -48 48
Wewaii [24]

The answer is -48

...............................................

8 0
4 years ago
Solve the simultaneous equations. <br>Y=5x^2 + 4x-19<br>Y=4x+1 ​
Olegator [25]

Answer: x1=-2

x2=2

Step-by-step explanation:

5x²+4x-19=4x+1

5x²+4x-19-4x-1=0

5x²-20=0

5x²=20

x²=20/5

x²=4

x1=-√4=-2

x2=+√4=2

8 0
4 years ago
How would u do 1 over 3 y + 1 over 4 = 5 over 12? I forgot my notes:(
malfutka [58]
Is it
\frac{1}{3y} + \frac{1}{4} = 5
or
\frac{1}{3} y + \frac{1}{4} = 5
?

both start out the same, just remember what you do to one side you have to do to the other, so subtract both sides by 1/4, then you want to get y alone, so either divide or multiply the 3 on both sides! let me know which it is and I can help you out more

[edit] it's the second, and not going to use cross multiplication.
added a picture that walks you through it :)

3 0
3 years ago
Fill in the missing Statement and Reason blanks for the two-column proofs.
Lyrx [107]
The two column reason statement is 4 and 5
3 0
3 years ago
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