The answer would be 6b-3c because a would cancel out and be 0
You will have 40 minutes before it it’s 100% loaded
Answer:
<h2> 8 cm³ </h2>
Step-by-step explanation:
➡️ Volume = r³
➡️ 2³
➡️ 8
Answer:
a) 0.125
b) 7
c) 0.875 hr
d) 1 hr
e) 0.875
Step-by-step explanation:l
Given:
Arrival rate, λ = 7
Service rate, μ = 8
a) probability that no requests for assistance are in the system (system is idle).
Let's first find p.
a) ρ = λ/μ

Probability that the system is idle =
1 - p
= 1 - 0.875
=0.125
probability that no requests for assistance are in the system is 0.125
b) average number of requests that will be waiting for service will be given as:
λ/(μ - λ)
= 7
(c) Average time in minutes before service
= λ/[μ(μ - λ)]
= 0.875 hour
(d) average time at the reference desk in minutes.
Average time in the system js given as: 1/(μ - λ)

= 1 hour
(e) Probability that a new arrival has to wait for service will be:
λ/μ =
= 0.875
The answer to this question is the school is going to have to rent 2 vans extra. The reason is because each van hols 8 people right. for the 6 vans that the school already owns, that will be 48 students in vans. When you subract that from 59, you get 11 students that still need a van, so 11 students can not fit in one extra van so the school would need two. Hope this gives you what you were looking for. God bless, and hope this helped. Also, please let me know if it was correct.