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Nataly [62]
3 years ago
12

Given two sets of parallel lines in the diagram below, what is the relationship between ∠ 9 and ∠ 3 ? image

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0
The relationship between angle nine and then go three is that they both are divisible by three 9÷3 is three and 3÷3 is one so that is the relationship between them
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Label the net for the figure below with its dimensions.
kogti [31]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below is the complete solution :
- two points on earth are :
(39N,120W) and (41N,84W)
midpoint between them = <span>(<span><span>39+41/</span>2</span>N, <span><span>120+84/</span>2</span>W)
= </span>(802N, 104/2W)
= <span>(40N,52W<span>)</span></span>
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Happy Paws charges $19.00 plus $3.50 per hour to keep a dog during the day. Woof Watchers charges $11.00 plus $4.75 per hour. Co
Nataly_w [17]
19.00 3.50 11.00 4.47 makes it add up to hours so that will be answe C
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Tell whether it is possible to draw a triangle with the given side lengths. 4 cm, 4 cm, 7 cm
Sati [7]
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5 0
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What is the distance around a triangle that has measuring 2 1/8 feet,3 1/2 feet, 2 1/2 feet
N76 [4]

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Hope this will help you!

3 0
3 years ago
App 19.study
lions [1.4K]

Answer:

1 \to 22 \to 0.176

2 \to 13 \to 0.104

3 \to 18 \to 0.144

4 \to 29 \to 0.232

5 \to 37 \to 0.296

6 \to 6 \to 0.048

Step-by-step explanation:

Given

n = 125

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

Pr = \frac{Frequency}{n}

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

Pr(2) = \frac{13}{125} = 0.104

Pr(4) = \frac{29}{125} = 0.232

Pr(6) = \frac{6}{125} = 0.048

When the frequency is to be calculated, we use:

Pr = \frac{Frequency}{n}

Frequency = n * Pr

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

Frequency(3) = 125 * 0.144 = 18

Frequency(5) = 125 * 0.296 = 37

For roll of 1 where the frequency and the probability are not known, we use:

Total \ Frequency = 125

So:

Frequency(1) added to others must equal 125

This gives:

Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125

Frequency(1) + 103 = 125

Collect like terms

Frequency(1) =- 103 + 125

Frequency(1) =22

The probability is then calculated as:

Pr(1) = \frac{22}{125}

Pr(1) = 0.176

So, the complete table is:

1 \to 22 \to 0.176

2 \to 13 \to 0.104

3 \to 18 \to 0.144

4 \to 29 \to 0.232

5 \to 37 \to 0.296

6 \to 6 \to 0.048

5 0
3 years ago
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