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likoan [24]
3 years ago
11

Mr. Chiro drew a design for an outdoor kitchen. The food prep area will be on a rectangular platform made of concrete that is 5

feet high. The storage shelf will be on a similar platform that is 6 feet high. What will be the total volume of the platforms?
Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

The volume of platform

= 11 ft³

Step-by-step explanation:

The height of the Platforms are

The food prep area  = 5 ft

Storage shelf = 6 ft

Side of rectangle = b width of platform = d

Therefore area of platform = b·d

Volume of the food prep area platform = Area × height = 5 b·d ft³

Volume of the storage shelf  platform = Area × height of storage shelf platform = 6 b·d ft³

Therefore the total volume = Volume of food storage platform + volume of storage shelf platform = 5 b·d ft³ + 6·b·d ft³ = 11·b·d ft³

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d1i1m1o1n [39]

<em><u>The solution is x = 8 and y = -5</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

x + y = 3 ------ eqn 1

3x + 2y = 14 ------ eqn 2

We have to find the solution to the equations

We can use substitution method to solve

From eqn 1,

x + y = 3

Isolate for "x"

x = 3 - y ------ eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

3(3 - y) + 2y = 14

9 - 3y + 2y = 14

-y = 14 - 9

-y = 5

<h3>y = -5</h3>

<em><u>Substitute y = -5 in eqn 3</u></em>

x = 3 - (-5)

x = 3 + 5 = 8

<h3>x = 8</h3>

Thus the solution is x = 8 and y = -5

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4 years ago
Five more than 6 times a number is 77.what is the number
Nadusha1986 [10]

Answer:

12

The drawing will help

4 0
3 years ago
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you are painting the outside of a 28 foot fence that goes around a square garden there are 4 equal sections. you have painted 1/
suter [353]

The answer is 1/8.

Hope this helps!

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3 years ago
Here guys the first one was wrong, write the numbers in words<br> 1,328,800.16<br> 15,802
grandymaker [24]
The 15,802 is
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4 years ago
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If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population fun
saw5 [17]

Answer:

The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ]  are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

Step-by-step explanation:

The given function is

P(t)=181843(1.04)^{(\frac{t}{10})}

where, P(t) is population after t years.

At t=5,

P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20

At t=6,

P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95

At t=7,

P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57

At t=8,

P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06

At t=9,

P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44

At t=10,

P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72

The rate of change of P(t) on the interval [x_1,x_2] is

m=\frac{P(x_2)-P(x_1)}{x_2-x_1}

Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is

m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504

The average rate of change of the population on the intervals [ 5 , 9 ] is

m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06

The average rate of change of the population on the intervals [ 5 , 8 ] is

m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62

The average rate of change of the population on the intervals [ 5 , 7 ] is

m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185

The average rate of change of the population on the intervals [ 5 , 6 ] is

m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75

Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ]  are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

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4 years ago
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