A 25 kg cart has 125 kg*m/s of momentum. How fast is the car going?

Physics

2 answers:

PSYCHO15rus [73]3 years ago

7 0

Therefore, the car is moving with a velocity of 5 m/s.

alisha [4.7K]3 years ago

3 0

Answer: 5

Explanation:

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How many joules of energy are required to accelerate one kilogram of mass from rest to a velocity of 0.866c?

Arlecino [84]

Answer:

the amount of energy needed is 1.8 x 10¹⁷ J.

Explanation:

Given;

mass of the object, m₀ = 1 kg

velocity of the object, v = 0.866 c

By physics convection, c is the speed of light = 3 x 10⁸ m/s

The energy needed is calculated as follows;

E = Mc²

As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;

$M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\ M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\ M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\ M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg$

The energy required is calculated as;

E = 2 x (3 x 10⁸)²

E = 1.8 x 10¹⁷ J

Therefore, the amount of energy needed is 1.8 x 10¹⁷ J.

3 0

3 years ago

The Petronas twin towers in Malaysia and the Chicago Sears tower have heights of about 452 m and 443 m respectively. If objects

fredd [130]

Answer:

0.09 s

Explanation:

From the second equation of motion,

$S=ut+\frac{1}{2}at^{2}$

Here, u is the initial velocity, a is the acceleration due to gravity, t is time taken, and S is the total displacement or distance.

From the given problem,

initial velocity is zero for both the case.

And the distance of twin tower of malaysia is, $S_{1}=452m$

And the distance of Sears tower of Chicago is, $S_{1}=443m$

Now,rearrange the distance equation for t.

$t=\sqrt{\frac{2S}{a} }$

So time difference.

$\Delta t=\sqrt{\frac{2(452)}{9.8} }-\sqrt{\frac{2(443)}{9.8} }\\\Delta t=\sqrt{92.244898}-\sqrt{90.4081633} \\\Delta t=9.60 s-9.51s\\\Delta t=0.09 s$