A sample of a gas in a rigid container has an initial pressure of 5 atm at a temperature of 254.5 k. The temperature is decrease
1 answer:
The gas is in a rigid container: this means that its volume remains constant. Therefore, we can use Gay-Lussac law, which states that for a gas at constant volume, the pressure is directly proportional to the temperature. The law can be written as follows:
Where P1=5 atm is the initial pressure, T1=254.5 K is the initial temperature, P2 is the new pressure and T2=101.8 K is the new temperature. Re-arranging the equation and using the data of the problem, we can find P2:
So, the new pressure is 2 atm.
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Using seconds equation of motion:
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Now, Acceleration down the incline = g Sin Θ
g Sin Θ = a
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Sin Θ =
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Hence, the angle of the inclined plane is: Θ = 12.31°
Answer:
<h2>The answer is 30 s</h2>Explanation:
The time taken can be found by using the formula
v is the velocity
a is the acceleration
From the question we have
We have the final answer as
<h3>30 s</h3>Hope this helps you