Density is calculated by dividing the ________ by the ________

we measure a voltage difference of 5.0 V between two points on the conducting paper between two parallel conducting electrodes.

Alex17521 [72]

Answer:

E=1824.81 V/m

Explanation:

Given that

Voltage difference = 5 V

Distance ,D= 3 mm

θ = 24°

As we know that electric filed given as

$E=\dfrac{V}{d}$

Given that D is 24° with respect to the perpendicular to the electrodes.So we have to take cos component of D.

d= D cosθ

d= 3 cos24°

d = 2.74 mm

So

$E=\dfrac{V}{d}$

$E=\dfrac{5}{2.74\times 10^{-3}}$

E=1824.81 V/m

8 0

3 years ago

Transition

Snezhnost [94]

Frozen water has move volume than water in liquid form

8 0

3 years ago

10) The closest star to the earth (other than

Reptile [31]

Answer:

It takes a little, be patient.

8 0

4 years ago

What force is needed to give a 4800.0 kg truck an acceleration of 6.2 m/s2 over a level road?

tekilochka [14]

Answer:

the force needed to give the truck the acceleration is 29,760 N.

Explanation:

Given;

mass of truck, m = 4800 kg

acceleration of the truck, a = 6.2 m/s²

The force needed to give the truck the acceleration is calculated as;

F = ma

F = 4800 x 6.2

F = 29,760 N

Therefore, the force needed to give the truck the acceleration is 29,760 N.

6 0

3 years ago

16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radi

ArbitrLikvidat [17]

The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C

<h3>What does Orbital speed depend on ?</h3>

The speed of an object travelling around a circle depends on two quantities namely;

Its angular velocity w

Its distance from the center of the circle.

Given that an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)

The given parameters are:

The mass of Saturn = 5.68 x 10^26 kg

The orbital radius = 3.00 x 105 km

G = 6.67 × 10-11 N·m2/kg2

Let us first calculate the gravitational field strength on the Saturn.

g = GM/r²

Substitute all the necessary parameters and convert km to m

g = (6.67 × $10^{-11}$ × 5.68 × $10^{26}$ ) ÷ (300000 × 1000)²

g = 3.79 × $10^{16}$ ÷ 9 × $10^{16}$

g = 0.421 m/s²

The orbital speed will be

V² = gr

V² = 0.4211 × 300000 × 1000

V² = 126333333.3

V = √126333333.3

V = 11239.8 m/s

Convert it to Km/s by dividing the answer by 1000

V = 11239.8/1000

V = 11.2 Km/s

Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s

Learn more about Orbital Speed here: brainly.com/question/22247460

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4 0

1 year ago

Density is calculated by dividing the ________ by the _________.

Density is calculated by dividing the by the _.