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densk [106]
3 years ago
15

A steel ball of mass 0.500 kg is fastened to a cord that is 70.0 cm long and fixed at the far end. The ball is then released whe

n the cord is horizontal. At the bottom of its path, the ball strikes a 2.50 kg steel block initially at rest on a frictionless surface. The collision is elastic. Find (a) the speed of the ball and (b) the speed of the block, both just after the collision.
Physics
1 answer:
Komok [63]3 years ago
6 0

Answer:

a) The speed of the ball is 2.47 m/s (in -x direction)

b) The speed of the block, both just after the collision is 1.236 m/s (in +x direction)

Explanation:

Please look at the solution in the attached Word file.

Download docx
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What is the total capacitance in units of mF, of the two capacitors connected in series, as shown in the diagram, when C1 = 45 m
elena-14-01-66 [18.8K]

Answer:

16.7 mF

Explanation:

The total capacitance of two capacitors connected in series is given by the formula:

\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}

in our problem, we have:

C1 = 45 mF is the capacitance of the first capacitor

C2 = 26 mF is the capacitance of the second capacitor

Substituting into the equation, we find:

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