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Schach [20]
3 years ago
15

Which of the following does light demonstrate?

Physics
2 answers:
pogonyaev3 years ago
7 0

Answer:

the answer is A

Explanation:

nataly862011 [7]3 years ago
4 0

Answer:

A

Explanation:

Light has both wave and particle characteristics. It behaves as wave in examples such as Reflection, refraction, diffraction, interference. It behaves as a particle in photoelectric effect, compton's effect etc. Light is an example of wave-particle duality.

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HELP ASAP TIMED TEST
balu736 [363]

Answer:

<em>Correct choice: b 4H</em>

Explanation:

<u>Conservation of the mechanical energy</u>

The mechanical energy is the sum of the gravitational potential energy GPE (U) and the kinetic energy KE (K):

E = U + K

The GPE is calculated as:

U = mgh

And the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

g = gravitational acceleration

h = height of the object

v = speed at which the object moves

When the snowball is dropped from a height H, it has zero speed and therefore zero kinetic energy, thus the mechanical energy is:

U_1 = mgH

When the snowball reaches the ground, the height is zero and the GPE is also zero, thus the mechanical energy is:

\displaystyle U_2=\frac{1}{2}mv^2

Since the energy is conserved, U1=U2

\displaystyle mgH=\frac{1}{2}mv^2    \qquad\qquad [1]

For the speed to be double, we need to drop the snowball from a height H', and:

\displaystyle mgH'=\frac{1}{2}m(2v)^2

Operating:

\displaystyle mgH'=4\frac{1}{2}m(v)^2 \qquad\qquad [2]

Dividing [2] by [1]

\displaystyle \frac{mgH'}{mgH}=\frac{4\frac{1}{2}m(v)^2}{\frac{1}{2}m(v)^2}

Simplifying:

\displaystyle \frac{H'}{H}=4

Thus:

H' = 4H

Correct choice: b 4H

4 0
2 years ago
How long will it take a person walking at 2.1 m/s to travel 13 m?
MrRissso [65]

Answer:

I gonna give you the number so but you need to round 6.19047619048

Explanation:

  • This is a speed formula so you would use the formula speed=distance/time
  • You need to rearrange it to time=distance/speed
  • So you need to divide 13m by 2.1 m/s

7 0
3 years ago
A mass m0 is attached to a spring and hung vertically. The mass is raised a short distance in the vertical direction and release
iragen [17]

Answer:

The frequency of the oscillations in terms of fo will be f2=fo/3

E xplanation:

T= 2pie\frac sqrt {m}{k}

 \frac {{f2}/times {fo}}=1:3

⇒f2=fo\3

Here frequency f is inversely poportional to square root of mass m.

so the value of remainder of frequency f2 and fo is equal to 1:3.

⇒\frac{f2} {f1} = \frac sqrt{m1}[m2}

⇒\frac{f2}{fo} = 1:3

⇒f2=\frac{fo} {3}

6 0
3 years ago
According to Charles’s law, when the temperature of a gas increases at constant pressure its a. volume increases. b. mass increa
xxMikexx [17]
The answer is A, the volume increases.
hope this helps
8 0
2 years ago
The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that
pav-90 [236]

Answer:

The permittivity of rubber is  \epsilon  = 8.703 *10^{-11}

Explanation:

From the question we are told that

     The  magnitude of the point charge is  q_1 =  70 \ nC  =  70 *10^{-9} \  C

      The diameter of the rubber shell is  d = 32 \ cm  =  0.32 \ m

       The Electric field inside the rubber shell is  E =  2500 \ N/ C

The radius of the rubber is  mathematically evaluated as

              r =  \frac{d}{2} =  \frac{0.32}{2}  =  0.16 \ m

Generally the electric field for a point  is in an insulator(rubber) is mathematically represented as

         E =  \frac{Q}{ \epsilon }  *  \frac{1}{4 *  \pi r^2}

Where \epsilon is the permittivity of rubber

    =>     E  *  \epsilon  *  4 * \pi *  r^2 =  Q

   =>      \epsilon  =  \frac{Q}{E *  4 *  \pi *  r^2}

substituting values

            \epsilon  =  \frac{70 *10^{-9}}{2500 *  4 *  3.142 *  (0.16)^2}

            \epsilon  = 8.703 *10^{-11}

7 0
3 years ago
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