Answer:
Explanation:
We apply Newton's second law:
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Problem development
M1 free body diagram : Look at the attached graphic
∑F = m₁*a
W₁ -T= m₁*a
W₁ - m₁*a = T Equation 1
M2 free body diagram :Look at the attached graphic
∑F = m₂*a
T-W₂= m₂*a
W₂ + m₂*a = T Equation 2
Equation 1 = Equation 2
W₁ - m₁*a = W₂ + m₂*a
W₁ - W₂ = m₁*a + m₂*a
m₁*g -m₂*g = a* (m₁ + m₂)
a = (m₁*g -m₂*g) / (m₁ + m₂)
Calculation of the tension in the rope (T)
We replace a in the equation 2
W₂ + m₂*a = T
W₂ + m₂*g*(m₁ -m₂) / (m₁ + m₂) = T
m₂*g + m₂*g*(m₁ -m₂) / (m₁ + m₂) = T
m₂*g( (1+ (m₁ -m₂)) / (m₁ + m₂) = T
m₂*g (1+m₁ -m₂) / (m₁ + m₂) = T
1 volt = 1 Joule per Coulomb.
24 J / 10 C = 2.4 J/C = 2.4 volts
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