Answer:5.45X10^3m
Explanation:So use the formula,v= fλ
3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer
Answer:
d. 87,500 J
e. 49,600 J
Explanation:
The total energy is the heat absorbed by the copper plus the heat absorbed by the water.
d)
E = m₁C₁ΔT + m₂C₂ΔT
E = (1 kg) (390 J/kg/°C) (10 °C) + (2 kg) (4180 J/kg/°C) (10 °C)
E = 87,500 J
e)
E = m₁C₁ΔT + m₂C₂ΔT
E = (2 kg) (390 J/kg/°C) (10 °C) + (1 kg) (4180 J/kg/°C) (10 °C)
E = 49,600 J
Answer:
-0.233 m left of diverging lens and ( 0.12 - 0.233 ) = -113 m left of conversing
and
0.023 m right of diverging lens
Explanation:
given data
focal length f2 = 14 cm = -0.14 m
Separation s = 12 cm = 0.12 m
focal length f1 = 21 cm = 0.21 m
distance u1 = 38 cm
to find out
final image be located and Where will the image
solution
we find find image location i.e v2
so by lens formula v1 is
1/f = 1/u + 1/v ...............1
v1 = 1/(1/f1 - 1/u1)
v1 = 1/( 1/0.21 - 1/0.38)
v1 = 0.47 m
and
u2 = s - v1
u2 = 0.12 - 0.47
u2 = -0.35
so from equation 1
v2 = 1/(1/f2 - 1/u2)
v2 = 1/(-1/0.14 + 1/0.35)
v2 = -0.233 m
so -0.233 m left of diverging lens and ( 0.12 - 0.233 ) = -113 m left of conversing
and
for Separation s = 45 cm = 0.45 m
v1 = 1/(1/f1 - 1/u1)
v1 =0.47 m
and
u2 = s - v1
u2 = 0.45 - 0.47 =- 0.02 m
so
v2 = 1/(1/f2 - 1/u2)
v2 = 1/(-1/0.14 + 1/0.02)
v2 = 0.023
so here 0.023 m right of diverging lens
The analogous formula for magnetic fields is the Ampere's law.
To find the answer, we need to know about the Ampere's law of magnetism.
<h3>What's Ampere's law of magnetism?</h3>
Ampere's law states that the close line integral of magnetic field around a current carrying loop is directly proportional to the current enclosed within it.
<h3>What's is the mathematical expression of Ampere's law?</h3>
Mathematically, Ampere's law is
B•dl= μ₀I
Thus, we can conclude that the analogous formula for gauss law is the Ampere's law in magnetism.
Learn more about the Ampere's law here:
brainly.com/question/17070619
#SPJ4
Answer:
2.25 %
Explanation:
65-95-99.7 is a rule to remember the precentages that lies around the mean.
at the range of mean (
) plus or minus one standard deviation (
), ![P([\mu-\sigma \leq X \leq \mu+\sigma])\approx 68.3%](https://tex.z-dn.net/?f=P%28%5B%5Cmu-%5Csigma%20%5Cleq%20X%20%5Cleq%20%5Cmu%2B%5Csigma%5D%29%5Capprox%2068.3%25)
at the range of mean plus or minus two standard deviation, ![P([\mu -2\sigma \leq X \leq \mu+2\sigma])\approx 95.5%](https://tex.z-dn.net/?f=P%28%5B%5Cmu%20-2%5Csigma%20%5Cleq%20X%20%5Cleq%20%5Cmu%2B2%5Csigma%5D%29%5Capprox%2095.5%25)
at the range of mean plus or minus three standard deviation, ![P([\mu - 3\sigma\leq X \leq \mu+3\sigma])\approx 99.7%](https://tex.z-dn.net/?f=P%28%5B%5Cmu%20-%203%5Csigma%5Cleq%20X%20%5Cleq%20%5Cmu%2B3%5Csigma%5D%29%5Capprox%2099.7%25)
So, note that they are asking about the probability that it is greater than 0.32, that is the mean (0.3) plus two times the standard deviation (0.1) (
)
So we know that the 95.5% is between 
and 
, hence approximately the 4.5% (100%-95.5%) is greater than 0.32 or less than 0.28. But half (4.5%/2=2.25%) is greater than 0.32 and the other half is less than 0.28.
So 
