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QveST [7]
3 years ago
15

You and your 3 friends are driving down the road. All the wheels go flat at the exact same time, that's not good. You have to us

e a 2,100 N force to push the car 4 meters to the side of the road. How much work did you do on the car?
Physics
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

Workdone = 8400 Nm

Explanation:

Given the following data;

Force = 2100 N

Distance = 4 meters

To find the work done;

Workdone = force * distance

Workdone = 2100 * 4

Workdone = 8400 Nm

Therefore, the amount of work done on the car is 8400 Newton meters.

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Symbol of ammonium is

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3 years ago
A motorcycle running on gasoline wastes a large amount of energy mainly as A) heat energy and sound energy. B) light energy and
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A motorcycle mainly wastes energy as heat <u>energy</u> and <u>sound</u> energy. In the engine, chemical energy is transformed into mechanical energy. However, the engine is inefficient and much of the chemical energy is lost as heat energy. Also, some of the energy is transformed to sound energy. This explains why the motorcycle is noisy and has an exhaust pipe.

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4 years ago
An igneous rock becomes buried, is subject to high heat and pressure, and recrystallizes. This rock then is eroded, transported,
nevsk [136]

Answer:

Answered

Explanation:

When an igneous rock becomes buried, is subjected to high heat and pressure, and recrystallizes it is formed into  Metamorphic rock. Now this rock is eroded, transported, deposited and subsequently lithified to be converted into Sedimentary rock.

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5 0
3 years ago
Karla Ayala pulls a sled on an icy road (dangerous!). Because of Karla's pull, the tension force is 151 N, and the rope makes a
skelet666 [1.2K]

Answer:

W = 1418.9 J = 1.418 KJ

Explanation:

In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:

W = F.d

W = Fd Cosθ

where,

W = Work Done = ?

F = Force = 151 N

d = distance covered = 10 m

θ = Angle with horizontal = 20°

Therefore,

W = (151 N)(10 m) Cos 20°

<u>W = 1418.9 J = 1.418 KJ</u>

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