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grandymaker [24]
3 years ago
13

A tennis ball covers a distance of 12 meters in 0.4 seconds what is the velocity of the tennis ball?

Physics
2 answers:
Usimov [2.4K]3 years ago
7 0
V=d/t
V=12/0.4
V=30 m/s
Ksenya-84 [330]3 years ago
4 0

Answer:

30m/s

Explanation:

Given parameters:

Distance  = 12m

Time taken  = 0.4s

Unknown:

Velocity of the tennis ball = ?

Solution:

Velocity of a body is the displacement per unit of time.

  Velocity  = \frac{displacement}{time}  

So;

      Velocity  = \frac{12}{0.4}   = 30m/s

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Three cars (car F, car G, and car H) are moving with the same speed and slam on their brakes. The most massive car is car F, and
Crazy boy [7]

To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.

From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

v_f^2=v_i^2+2ax

Where,

v_f = Final velocity

v_i = Initial Velocity

a = Acceleration

x = Displacement

Acceleration can be expressed in terms of the drag coefficient by means of

F_f = \mu_k (mg)  \rightarrowFrictional Force

F = ma \rightarrow Force by Newton's second Law

Where,

m = mass

a= acceleration

\mu_k = Kinetic frictional coefficient

g = Gravity

Equating both equation we have that

F_f = F

\mu_k mg=ma

a = \mu_k g

Therefore,

v_f^2=v_i^2+2ax

0=v_i^2+2(\mu_k g)x

Re-arrange to find x,

x = \frac{v_i^2}{2(-\mu_k g)}

The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.

3 0
3 years ago
Rae has just heard a loud crash from her garage. The impact of the sound wave bouncing against her eardrum sets off a chain reac
matrenka [14]

Answer:

Hammer

Anvil

Stirrup

Explanation:

The three tiny bones in the ear drum are:

Hammer, this is also known as malleus and it is attached to the eardrum

Anvil, this is also called incus and it found with the chain of bones in the middle ear.

Stirrup, also known as stapes and it attached to the membrane covered opening that connects the middle ear with the inner ear.

7 0
3 years ago
Jenny and Alyssa are members of the cross-country team. On a training run, Jenny starts off and runs at a constant 3.8 m/s. Alys
guapka [62]

Answer:

285 seconds

Explanation:

Jenny speed is 3.8 m/s

Alyssa speed in 4.0 m/s

Alyssa starts after 15 seconds

Find the distance covered by Jenny, when Alyssa starts

Distance=Speed*time

Distance covered by Jenny in 15 seconds= 3.8×15=57m

Relative speed of the two members heading same direction will be;

4.0m/s-3.8m/s=0.2m/s

To find the time Alyssa catch up with Jenny you divide the distance to be covered by Alyssa by the relative speed of the two

Distance=57m, relative speed=0.2m/s  t=57/0.2 =285 seconds

=4.75 minutes

5 0
3 years ago
Read 2 more answers
A 38.5kg man is in an elevator accelerating downward. A normal force of 343n pushes up on him. what is his acceleration?
alexira [117]

Answer:

<h3>The answer is 8.91 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{343}{38.5}  =  \frac{98}{11}  \\  = 8.909090...

We have the final answer as

<h3>8.91 m/s²</h3>

Hope this helps you

4 0
3 years ago
A dart is loaded into a spring-loaded toy dart gun by pushing the spring in by a 
distance d. For the next loading?the spring is
Mrac [35]

Answer:

W'=\dfrac{W}{9}

Explanation:

The potential energy of the spring or the work done by the spring is given by :

W=\dfrac{1}{2}kd^2............(1)

k is the spring constant

d is the compression

When the spring is compressed a distance d' = d/3, let W' is the work is required to load the second dart. Then the work done is given by :

W'=\dfrac{1}{2}kd'^2

W'=\dfrac{1}{2}k(d/3)^2.............(2)

Dividing equation (1) and (2) :

\dfrac{W}{W'}=\dfrac{1/2kd^2}{1/2k(d/3)^2}

\dfrac{W}{W'}=9

W'=\dfrac{W}{9}

So, the work required  to load the second dart compared to that required to load the first is one-Ninth as much. Therefore, the correct option is (E).

7 0
3 years ago
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