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Keith_Richards [23]
3 years ago
9

A pebble is released from rest at a certain height and falls freely, reaching an impact speed of 6 m/s at the floor. Next, the p

ebble is thrown down with an initial speed of 3 m/s from the same height. What is its speed at the floor
Physics
1 answer:
Anna71 [15]3 years ago
8 0

Answer:

Explanation:

Let h be the height .

initial velocity in first case u = 0

final velocity v = 6 m /s

acceleration due to gravity g = 9.8 m /s²

v² = u² + 2 g h

6² = 0 + 2 x 9.8 x h

h = 1.837 m .

For second case u = 3 m /s

v² = u² + 2 gh

= 3² + 2 x 1.837 x 9.8

= 9 + 36

= 45 m

v = 6.7 m /s

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Frosty the Snowman accelerates from 16 m/s to 26 m/s in 2 s. What is his acceleration?
Alex_Xolod [135]

Answer:

his acceleration is 3.25

Explanation:

because you do 26÷16 which =1.625×2=3.25

6 0
3 years ago
A pump is used to lift 100 KG of water from a wel 60 m deep,in 20 S If force of gravity on 1 KG is 10 N,find
Harlamova29_29 [7]

Explanation:

Given,

  • m = 100 kg
  • g = 10 N/kg¹
  • h = 60 m
  • t = 20 s

To Find:

a) Work done by the pump

b) Potential energy stored in the water

c)Power spent by the pump

d)Power rating of the pump.

Solution:

  • a) Work done by the pump

We know that,

\rm \: Work  \: done = Force * Distance  \: moved

  • f = 100 kg * 10N/kg
  • d = 60 m

\rm \: Work\; Done =(100 \: kg \times  \cfrac{10N}{kg} ) \times 60 \: m

\rm \: Work\; Done =1000 \times 60 \: joule

\boxed{\rm \: Work\; Done =60000 \: joule}

[The unit'll be joule since N×M = J]

  • b) Potential energy stored in the water

\rm \: P.E = m \cdot g \cdot  h

  • m = 100 kg
  • g = 10N/kg
  • h = 60

\rm \: P.E =100 \:kg \:  \times  \cfrac{10 \: N}{kg}  \times 60

\boxed{\rm \: P.E =60000  \: joule}

  • same condition here as well, N×M = J
  • c) Power of the Pump

\rm \: P = W/T

  • where P = Power; W = Work done & T = Time taken
  • As we got the value of work done on question (a),& ATQ time taken is 20 S.

\rm \: P =  \cfrac{60000 \: joule}{20 \: seconds}  =\boxed{\rm { 3000 \: Watts }}\: or \: \boxed{\rm 3 \: kW}

  • d) Power rating of the pump = 3 kW

Assumption: The pump is 100% efficient & works well.

6 0
2 years ago
A helicopter goes straight up 500m from a landing pad. It then goes north 20m. Then it goes down 452m. a) What is the displaceme
gavmur [86]

Answer:

a

  x-component             20 \  m

y-component     500 -  452 =  48 \  m

b

 Magnitude d  =  52 \  m

direction is  \theta  = 67.4^o

Explanation:

From the question we are told that

   The first  vertical distance is  y_1   = 500 \  m

    The  first horizontal distance  is  x =  20 \  m

    The  second vertical distance is  y_2  =  452 \  m

Generally the displacement is  

x-component             20 \  m

y-component     500 -  452 =  48 \  m

Generally the helicopters displacement is mathematically evaluated as  

       d  =  \sqrt{ x- component ^2  +  y- component ^2 }

      d  =  \sqrt{ 20t ^2  + 48 ^2 }

      d  =  52 \  m

The  direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as

         \theta  = tan ^{-1}[ \frac{48}{20}]

=>       \theta  = tan ^{-1}[ 2.4 ]

=>      \theta  = 67.4^o

   

3 0
3 years ago
You are not allowed to park within
aleksandr82 [10.1K]

Answer:

The correct answer is - 30 feet.

Explanation:

According to the parking laws one should not park within 30 feet of any flashing signal, stop sign, or traffic signal it is not allowed. Parking is also not allowed in case of the following situations -

On crosswalks

In front of driveways

double parking

On sidewalks.  

at "No Parking" signs are posted.

Within intersections or 20 feet of an intersection.

Within 15 feet of a fire hydrant.

 

8 0
3 years ago
Read 2 more answers
A 40.0-kg football player leaps through the air to collide with and tackle a 50.0-kg player heading toward him, also in the air.
lara31 [8.8K]

Answer:

The speed and direction of the tangled players is 2.89 m/s towards right.

Explanation:

Given;

mass of the player heading right, m₁ = 40 kg

initial velocity of the player heading right, u₁ = 9.0 m/s

mass of the player heading left, m₂ = 50 kg

initial velocity of the player heading left, u₂ = -2.0 m/s

let the speed of the tangled players = v

Apply the law of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(40 x 9) + (50 x - 2) = v(40 + 50)

360 - 100 = v(90)

260 = v(90)

v = 260 / 90

v = 2.89 m/s (towards right, since it is in position direction)

Therefore, the speed and direction of the tangled players is 2.89 m/s towards right.

5 0
3 years ago
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