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Sunny_sXe [5.5K]
3 years ago
12

Niels Bohr's important discovery was?

Physics
2 answers:
Tom [10]3 years ago
7 0
In 1912, Bohr<span> was working for the Nobel laureate J.J. Thompson in England when he was introduced to Ernest Rutherford, whose </span>discovery<span> of the nucleus and development of an atomic model had earned him a Nobel Prize in chemistry in 1908. Under Rutherford's tutelage, </span>Bohr<span> began studying the properties of atoms.

</span>
just olya [345]3 years ago
5 0
Niel Bohr contributed to science by helping people understand the structure and energy of the atom.
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What is the length of 0.005 mm in kilometers?
ZanzabumX [31]
The answer would be 5*10^9&#10;.

If we divide \frac{5*10^9}{1*10^6}, it gives us 0.005!

Hope this helped! c:
4 0
3 years ago
The picture below shows a football player kicking a football. This is known as two dimensional motion. In which direction does t
Molodets [167]

You are true, Stokey.  The correct choice is<em> (c)</em>.

If you think about it a little bit more, you'll realize that "side to side" is also a horizontal motion.  

Anyway, the question told us that we're only talking about 2 dimensions.  Well, the The measurements in the 2 dimensions are the x and the y .  If there were a z measurement, that would be the 3rd dimension.

7 0
3 years ago
An air-track glider with a mass of 239 g is moving at 0.81 m/s on a 2.4 m long air track. It collides elastically with a 513 g g
HACTEHA [7]

Answer:

Glider it stops just when it reaches the end of the runway

Explanation:

This is a shock between two bodies, so we must use the equations of conservation of the amount of movement, in the instant before the crash and the subsequent instant, with this we calculate the second glider speed, as the shock that elastic is also keep it kinetic energy

        Po = pf

        Ko = Kf

 Before crash

       Po = m1 Vo1 + 0

       Ko = ½ m1 Vo1²

 

After the crash

       Pf = m1 Vif + Vvf

       Kf = ½ m1 V1f² + ½ m2 V2f²

 

      m1 V1o = m1 V1f + m2 V2f           (1)

      m1 V1o² = m1 V1f² + m2 V2f²      (2)

We see that we have two equations with two unknowns, so the system is solvable,  we substitute in 1 and 2

   

     m1 (V1o -V1f) = m2 V2f      (3)

      m1 (V1o² - V1f²) = m2 V2f²

Let's use the relationship      (a + b) (a-b) = a² -b²

     m1 (V1o + V1f) (V1o -V1f) = m2 V2f²

We divide  with 3 and simplify

      (V1o + V1f) = V2f      (4)

Substitute in 3, group and clear

         m1 (V1o - V1f) = m2 (V1o + V1f)

         m1 V1o - m2 V1o = m2 V1f + m1 V1f

         V1f (m1 -m2) = V1o (m1 + m2)

         V1f = V1o  (m1-m2 / m1+m2)

We substitute in (4) and group

         V2f = V1o + (m1-m2 / m1 + m2) V1o

         V2f = V1o [1+ + (m1-m2 / m1 + m2)]

         V2f = V1o (2m1 / (m1+m2)

We calculate with the given values

         V1f = 0.81 (239-513 / 239 + 513)

         V1f = 0.81 (-274/752)

         V1f = - 0.295 m/s

The negative sign indicates that the planned one moves in the opposite direction to the initial one

         V2f = 0.81 [2 239 / (239 + 513)]

        V2f = 0.81 [0.636]

        V2f = 0.515 m / s

Now we analyze in the second glider movement only, we calculate the energy and since there is no friction,

         Eo = Ef

Where Eo is the mechanical energy at the lowest point and Ef is the mechanical energy at the highest point

         Eo = K = ½ m2 vf2²

         Ef = U = m2 g Y

   

         ½ m2 v2f² = m2 g Y

         Y = V2f² / 2g

         Y = 0.515²/2 9.8

         Y = 0.0147 m

At this height the planned stops, let's use trigonometry to find the height at the end of the track of the track

         tan θ = Y / x

         Y = x tan θ

The crash occurs in the middle of the track whereby x = 1.2 m

        Y = 1.2 tan 0.7

        Y = 0.147 m

As the two quantities are equal in glider it stops just when it reaches the end of the runway

7 0
3 years ago
Name the plate boundary responsible for this.<br><br> Please help!!
Korolek [52]
Continental crust plate name
5 0
3 years ago
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Which waves can travel through space?
xz_007 [3.2K]

Answer:

electromagnetic waves only

Explanation:

I just took the test, Hope it helps!

4 0
3 years ago
Read 2 more answers
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