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zhuklara [117]
2 years ago
10

UTMSUNG

Physics
1 answer:
likoan [24]2 years ago
4 0

Answer:

i think answer id leech because when it move it leave the liner

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You watch a distant lady driving nails into her front porch at a regular rate of 1 stroke per second. You hear the sound of the
Igoryamba

Answer:

λ = 1360 m

Explanation:

Given data:

frequency of driving nails is given as 1 stroke per second mean at every 0.25 sec she hit the nails

speed of sound is given as 340 m/s

we know that the wave equation is given as

Speed = frequency × wavelength,

v = f × λ

where,

v = speed in meters/second (m/s)

f = frequency in Hertz (Hz)

substituing value to get wavelength  of her driving nails

340 m/s = (1Hz)\times  \lambda

\lambda = \frac{340}{0.25}

λ = 1360 m

4 0
3 years ago
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Physics is defined as:
nikitadnepr [17]

Answer:

B. Developed out of efforts of man trying to explain our physical environment.

Explanation:

This is because physics, as we all know of, is considered to be <em>crucial to understanding the world around us</em>, making it the most basic and fundamental of science.

5 0
3 years ago
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A force of 500 N is exerted on a baseball by the bat for 0.001 s. What is the change in momentum of the baseball?
GarryVolchara [31]
Answer: Δp = F*Δt = 500N*0.001s = 0.5Ns
3 0
3 years ago
What I Know True or False. Read each statement carefully. Identify whether the statement is true or false. Write your answer on
timofeeve [1]

Answer:

1. False

2. True

3. True

4. True

5. True

6. False

7. True

8. False

9. False

10. True

11. True

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7 0
3 years ago
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A 110-kg object and a 410-kg object are separated by 3.80 m.
aniked [119]

Answer:

a)   Fₙ = 2,273 10⁻⁷ N   and   b)    x₃ = 1,297 m

Explanation:

This problem can be solved using the law of universal gravitation and Newton's second law for the equilibrium case. The Universal Gravitation Equation is

    F = G m₁ m₂ / r₁₂²

a) we write Newton's second law

       Σ F = F₁₃ - F₃₂

Body 1 has mass of m₁ = 110 kg and we will place our reference system, body 2 has a mass of m₂ = 410 kg and is in the position x₂ = 3.80 m

Body 3 has a mass of m₃ = 41.0 kg and is in the middle of the other two bodies

      x₃ = (x₂-x₁) / 2

     x₃ = 3.80 / 2 = 1.9 m

     Fₙ = -G m₁ m₃ / x₃² + G m₃ m₂ / x₃²

     Fₙ = G m₃ / x₃² (-m₁ + m₂)

Calculate

     Fₙ = 6.67 10⁻¹¹ 41.0 / 1.9² (- 110 + 410)

     Fₙ = 2,273 10⁻⁷ N

Directed to the right

b) find the point where the force is zero

The distance is

     x₁₃ = x₃ - 0

    x₃₂ = x₂ -x₃= 3.8 -x₃

We write the park equation net force be zero

     0 = - F₁₃ + F₃₂

     F₁₃ = F₃₂

     G m₁ m₃ / x₁₃² = G m₃ m₂ / x₃₂²

     m₁ / x₁₃² = m₂ / x₃₂²

Let's look for the relationship between distances, substituting

     m₁ / x₃² = m₂ / (3.8 - x₃)²

     (3.8 - x₃) = x₃ √ (m₂ / m₁)

     x₃ + x₃ √ (m₂ / m₁) = 3.8

     x₃ (1 + √ m₂ / m₁) = 3.8

     x₃ = 3.8 / (1 + √ (m₂ / m₁))

     x₃ = 3.8 / (1 + √ (410/110))

     x₃ = 1,297 m

When body 3 is in this position the net force on it is zero

8 0
3 years ago
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