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galina1969 [7]
2 years ago
12

A student measures out 5.0 g of magnesium and burns it. After the reaction, the student

Physics
1 answer:
kondor19780726 [428]2 years ago
4 0

Answer:

The answer is 2.9. g

Explanation:

7.9 - 5.0 = 2.9

I hope this helps!

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Two balls, ball A and ball B, are dropped from the same height onto the same surface. If ball A rebounds to a higher height than
mamaluj [8]

Answer:

its b

Explanation:

3 0
2 years ago
If a reaction starts with 30 grams how many should it end with ?
zysi [14]

30grams

Explanation:

If a reaction starts with 30grams then the reaction should end with 30grams.

This in conformity with the law of conservation of mass.

  • The law states that "in an isolated system, mass is neither created nor destroyed during chemical transformation".
  • Mass is the quantity of matter contained in a substance.
  • In chemical reactions, the mass of reactants must always be the same with the mass of the product baring any loss.
  • In an isolated system, there is no exchange of energy and mass.
  • Chemical systems are usually treated as isolated systems in which mass is conserved.

Learn more:

Chemical laws brainly.com/question/5896850

#learnwithBrainly

4 0
3 years ago
A parallel-plate capacitor is charged by connecting it to a battery. If the battery is disconnected and then the separation betw
TEA [102]

Answer:

The charge stored in the capacitor will stay the same. However, the electric potential across the two plates will increase. (Assuming that the permittivity of the space between the two plates stays the same.)

Explanation:

The two plates of this capacitor are no longer connected to each other. As a result, there's no way for the charge on one plate to move to the other. Q, the amount of charge stored in this capacitor, will stay the same.

The formula \displaystyle Q = C\, V relates the electric potential across a capacitor to:

  • Q, the charge stored in the capacitor, and
  • C, the capacitance of this capacitor.

While Q stays the same, moving the two plates apart could affect the potential V by changing the capacitance C of this capacitor. The formula for the capacitance of a parallel-plate capacitor is:

\displaystyle C = \frac{\epsilon\, A}{d},

where

  • \epsilon is the permittivity of the material between the two plates.
  • A is the area of each of the two plates.
  • d is the distance between the two plates.

Assume that the two plates are separated with vacuum. Moving the two plates apart will not affect the value of \epsilon. Neither will that change the area of the two plates.

However, as d (the distance between the two plates) increases, the value of \displaystyle C = \frac{\epsilon\, A}{d} will become smaller. In other words, moving the two plates of a parallel-plate capacitor apart would reduce its capacitance.

On the other hand, the formula \displaystyle Q = C\, V can be rewritten as:

V = \displaystyle \frac{Q}{C}.

The value of Q (charge stored in this capacitor) stays the same. As the value of C becomes smaller, the value of the fraction will become larger. Hence, the electric potential across this capacitor will become larger as the two plates are moved away from one another.  

3 0
3 years ago
What is the function (job) of the genes in protein synthesis (how proteins are made in the cell)?
Alborosie

Answer:Most genes contain the information needed to make functional molecules called proteins. (A few genes produce regulatory molecules that help the cell assemble proteins.) The journey from gene to protein is complex and tightly controlled within each cell. It consists of two major steps: transcription and translation.

Explanation:

5 0
2 years ago
A baseball is thrown at an angle of 20° relative to the ground at a speed of 25 m/s if the ball was caught 50 m from the thrower
scoray [572]

Answer:

2.1 s

Explanation:

The motion of the ball is a projectile motion. We know that the horizontal range of the ball is

d = 50 m

And that the initial speed of the ball is

u=25 m/s

at an angle of

\theta=20^{\circ}

So, the horizontal speed of the ball (which is constant during the entire motion) is

u_x = u cos \theta = 25 \cdot cos 20^{\circ} = 23.5 m/s

And since the horizontal range is 50 m, the time taken for the ball to cover this distance was

t=\frac{d}{u_x}=\frac{50}{23.5}=2.1 s

which is the time the ball spent in air.

8 0
2 years ago
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