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enot [183]
3 years ago
9

When the thermal energy of a material decreases, _____.

Physics
2 answers:
Pani-rosa [81]3 years ago
8 0
The surrounding environment cool off is the answer
Shtirlitz [24]3 years ago
4 0

D. The surrounding environment cools off



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g a stone with mass m=1.60 kg IS thrown vertically upward into the air with an initial kinetic energy of 470 J. the drag force a
otez555 [7]

Answer:

Height reached will be 28.35 m

Explanation:

Here we can use the work energy theorem to find the maximum height

As we know by work energy theorem

Work done by gravity + work done by friction = change in kinetic energy

-mgh - F_f h = 0 - \frac{1}{2}mv_i^2

now we will have

-1.60(9.8)(h) - 0.900(h) = - 470

-16.58 h = -470

h = 28.35 m

so here the height raised by the stone will be 28.35 m from the ground after projection in upward direction

5 0
3 years ago
An air-track cart is attached to a spring and completes one oscillation every 5.67 s in simple harmonic motion. at time t = 0.00
Masteriza [31]
The cart is moving by simple harmonic motion, and its position at time t is described by
x(t) = A \cos (\omega t)
where
A is the amplitude of the oscillation
\omega is the angular frequency

The amplitude of the oscillation corresponds to the maximum displacement of the spring, which corresponds to the initial position where the spring was released: 
A=0.250 m

The period of the motion is T=5.67 s, and the angular frequency is related to the period by
\omega =  \frac{2 \pi}{T}= \frac{2 \pi}{5.67 s} =1.11 rad/s

Therefore now we can calculate the position of the system at the time t=29.6 s:
x(29.6 s)=(0.250 m)\cos ((1.11 rad/s)(29.6 s))=+0.033 m
3 0
3 years ago
Read 2 more answers
The change in momentum of a body weighing 5 kg when its velocity increases from 10 m/s to 20 m/s in 10 s will be- PLEASEEE HELPP
Tanzania [10]

Answer:

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5 0
3 years ago
A force of 5N compresses a spring by 4cm. Find the force constant of the spring.​
marissa [1.9K]

Answer:

k = 1,250 N/m

Explanation:

Use the formula F=kx, with F=5N and x=0.04m

Then the spring constant (k) is 5/0.04

6 0
3 years ago
All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is
andre [41]
The acceleration is defined as the rate of change of velocity.
So, if the acceleration is zero, this means that the rate of change of velocity is zero, which also means that the body is moving with constant velocity.
Since we are given that the net forces acting on the body is zero, this means that the body is at equilibrium

Based on this:
<span>All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is in a state known as equilibrium.

Note that if this constant velocity is equal to zero, then the body would be at rest (not moving)</span>
7 0
3 years ago
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