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alexandr402 [8]
3 years ago
7

A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used

as a filament in an incandescent light bulb. When the light bulb is connected to a battery, a current of 0.526 A is measured through the filament. (Note: tungsten has a resistivity of 4.9 × 10-8 ? • m.) How many electrons pass through this filament in 5 seconds?
How many electrons pass through this filament in 5 seconds? 4.22 × 10-19 2.63 3.29 × 1018 1.64 × 1019

What is the resistance of this filament? What is the resistance of this filament? 4.28 ? 58.5 m? 17.1 ? 9.0 ?

What is the voltage of the battery that would produce this current in the filament? 31 mV 9.0 V 2.6 × 10-8 V 32 V

Physics
1 answer:
AleksAgata [21]3 years ago
3 0

Explanation:

Below is an attachment containing the solution.

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A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi
slega [8]
We divide the thin rectangular sheet in small parts of height b and length dr. All these sheets are parallel to b. The infinitesimal moment of inertia of one of these small parts is
dI =r^2*dm
where dm =M(b*dr)/(ab)
Now we find the moment of inertia by integrating from -a/2 to a/2
The moment of inertia is
I= \int\limits^{-a/2}_{a/2} {r^2*dm} = M \int\limits^{-a/2}_{a/2} r^2(b*dr)/(ab)=(M/a)(r^3/3) (from (-a/2) toI=(M/3a)(a^3/8 +a^3/8)=(Ma^2)/12 (a/2))



4 0
3 years ago
-poopp poopoop jujuj
san4es73 [151]

Answer:

okay.........

Explanation:

3 0
3 years ago
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The unit of measurement "mL" describes what property of a substance?
pychu [463]
<span>D. density is your answer</span>
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3 years ago
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A 25 kg rock resting on the bottom of a lake must be moved from the paths of boats. The rock has a density of 2350 kg/m^3. What
algol13

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7 0
3 years ago
A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a
Zolol [24]
     Considering the unknown resistence as R and using the Ohm's First Law, we have:

i= \frac{V}{R_{eq}}  \\ 0.5= \frac{12}{R+10}  \\ R+10=24 \\ R=14-Ohm
 
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R_{eq}=R+10 \\ R_{eq}=14+10 \\ \boxed {R_{eq}=24-Ohm}

If you notice any mistake in my english, please let me know, because i am not native.

6 0
2 years ago
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