A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used
as a filament in an incandescent light bulb. When the light bulb is connected to a battery, a current of 0.526 A is measured through the filament. (Note: tungsten has a resistivity of 4.9 × 10-8 ? • m.) How many electrons pass through this filament in 5 seconds?
How many electrons pass through this filament in 5 seconds? 4.22 × 10-19 2.63 3.29 × 1018 1.64 × 1019
What is the resistance of this filament? What is the resistance of this filament? 4.28 ? 58.5 m? 17.1 ? 9.0 ?
What is the voltage of the battery that would produce this current in the filament? 31 mV 9.0 V 2.6 × 10-8 V 32 V
How many electrons pass through this filament in 5 seconds? 4.22 × 10-19 2.63 3.29 × 1018 1.64 × 1019
What is the resistance of this filament? What is the resistance of this filament? 4.28 ? 58.5 m? 17.1 ? 9.0 ?
What is the voltage of the battery that would produce this current in the filament? 31 mV 9.0 V 2.6 × 10-8 V 32 V
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Answer:
Explanation:
Total letters available on the keyboard = 26
Doubling this amount to account for both upper and lower case letters.
Therefore, Total characters (Upper + Lower Case) = 52 characters
Total numbers on keyboard (0, 1, 2, 3, 4, 5, 6, 7, 8, 9) = 10 characters
Underscore = 1 character
Thus, Total allowed characters = 52 + 10 + 1 = 63
This is a problem of the permutation as order of the characters results in a different name.
Our file name should be of atleast 3 and smaller than 7 (i.e. 6) characters
Therefore, total possible permutations can be obtained by subtraction permutation of 2 characters from the permutations of 6 characters.