<h3>Answer</h3><h3>7 Ns</h3><h3>Explanation</h3>
Given in the question,
mass of foul ball = 0.140 kg
initial speed with which ball was hit with the bat = 30 m/s
final speed = 40 m/s
According to the scenario the whole scene is making a right angle triangle
So, to the solve the question we will use pythagorus theorem
<h3>Hypotenuse² = base² + height²</h3>
Here,
Hypotenuse= Magnitude of impulse
Base = 1st change of momentum
height = 2nd change of momentum
1st impulse (1st change of momentum)
p = m(1)v(1) = (0.14 kg)(40.0 m/s) = 5.6 kg m / s = 5.6 N s
2nd impulse (2nd change of momentum)
p = m(2)v(2) = (0.14 kg)(30.0 m/s) = 4.2 kg m / s = 4.2 N s
Magnitude of impulse (hypotenuse of triangle)
impulse² = (5.6)² + (4.2)²
impulse² = 31.36 + 17.64
impulse² = 49
impulse² = √49
impulse = 7.0 N s
Yes , increased tension suggests increased molecular attraction between the molecules of the ropes which affect the increase in the speed of wave.
Answer:
The forces that do non-zero work on the block are gravity and normal reaction force
Explanation:
Answer:
The cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.
Explanation:
From the question given above, the following data were obtained:
Height to which the target is located = 50 m
Initial velocity (u) = 20 m/s
To know whether or not the cannon ball is able to hit the target, we shall determine the maximum height to which the cannon ball attained. This can be obtained as follow:
Initial velocity (u) = 20 m/s
Final velocity (v) = 0 (at maximum height)
Acceleration due to gravity (g) = 10 m/s²
Maximum height (h) =?
v² = u² – 2gh (since the ball is going against gravity)
0² = 20² – (2 × 10 × h)
0 = 400 – 20h
Collect like terms
0 – 400 = – 20h
– 400 = – 20h
Divide both side by – 20
h = – 400 / – 20
h = 20 m
Thus, the the maximum height to which the cannon ball attained is 20 m.
From the calculations made above, we can conclude that the cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.
Answer:
The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.
At point B, Alberto's distance covered increases with time, equal distance is covered in equal time interval. The speed increases uniformly. At the point C to D, the distance covered with time remains the same. At the point D, equal distance is no longer covered in equal time intervals.
According to the law of inertia, an object will remain at rest or in a state of uniform motion unless it is acted upon by an unbalanced force. This means that smokey mouse will continue moving uniformly unless a force acts on it.
From Newton's second law; F = ma and a = F/m. F = force , m= mass, a = acceleration. This implies that smokey mouse can increase its speed by;
Increasing the force acting on the mouse
Decreasing the mass of the mouse
Action and reaction is encountered as the mouse is walking. The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.
Explanation:
