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MA_775_DIABLO [31]
2 years ago
10

Why is copper NOT used as a filament?

Physics
1 answer:
chubhunter [2.5K]2 years ago
6 0

Answer:

Short answer, because copper wire does not have high resistance.

Explanation:

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A pendulum has a mass of 0.060 kg swinging at a small angle from a light string, with a period of 1.4 s. What is the length of t
jok3333 [9.3K]

Answer:

0.5 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 0.060 kg

Period (T) = 1.4 s

Lenght (L) =?

NOTE:

1. Acceleration due to gravity (g) = 10 m/s²

2. Pi (π) = 3.14

The length of the pendulum can be obtained as follow:

T = 2π√(L/g)

1.4 = 2 × 3.14 × √(L/10)

1.4 = 6.28 × √(L/10)

Divide both side by 6.28

1.4 / 6.28 = √(L/10)

Take the square of both side

(1.4 / 6.28)² = L/10

Cross multiply

L = 10 × (1.4 / 6.28)²

L = 0.5 m

Therefore, the length of the pendulum is 0.5 m

4 0
3 years ago
Read 2 more answers
If the world population grows at a constant rate of 1.8% per annum, how many years will it take to double? A) 17.7 years
AleksandrR [38]

Answer:

after 38.8 years it will double

correct option is D 38.8 years

Explanation:

given data

population grows rate = 1.8%

to find out

how many years will it take to double

solution

we consider here initial population is x

so after 1 year population will be = (100% + 1.8% ) x = 1.018 x

and after n year population will be = 1.018^{n} x

so it will double

2x = 1.018^{n} x

take log both side

log 2 = n log (1.018)

n = \frac{log2}{log1.018}

n = 38.853

so after 38.8 years it will double

correct option is D 38.8 years

4 0
3 years ago
If you were to yell at a canyon wall, you would hear yourself a short time later. This is because sound can be
mojhsa [17]
The answer is answer b refracted

5 0
3 years ago
Read 2 more answers
Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?
Hitman42 [59]

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

h = \frac{v^{2}}{2g}

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

\frac{mv^{2}}{2} = mgh

h = \frac{v^{2}}{2g}

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

7 0
2 years ago
An object is dropped from a platform 100 feet high. Ignoring wind resistance, what will its speed be when it reaches the ground?
ICE Princess25 [194]

<span>if we assume the origin is at the dropping point and the object is merely dropped and not thrown up or down then y0 = 0 and v0 = 0. The equation reduces to </span>

<span>y = 0 + 0t + ½gt² </span>
<span>y = ½gt² </span>

<span>t = √(2y/g) </span>

<span>in the ft - lb - s system </span>

<span>y = -100 ft </span>
<span>g = -32.2 ft / s² </span>

<span>t = √(2y/g) </span>
<span>t = √(2(-100) / (-32.2)) </span>
<span>t = 2.5 s</span>
7 0
3 years ago
Read 2 more answers
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