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IgorC [24]
4 years ago
12

Hannah walked 3/4 of the way from school to her home. A.What fractional part of the distance does she have left to walk? b.The r

emaining distance is what fractional part of the distance she has already walked?
Mathematics
1 answer:
natita [175]4 years ago
7 0

Answer: A. 1/4 left

Step-by-step explanation:

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Which lines are parallel? Justify your answer.
Eddi Din [679]

Answer:

a and f

Step-by-step explanation:

jajsbzjslNzjskK z

7 0
3 years ago
Read 2 more answers
Which graph represents the function of f(x) 9x^2 -36 / 3x + 6
Finger [1]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

f(x)=\frac{9x^{2}-36}{3x+6}

Remember that the denominator cannot be equal to zero

so

The value of x cannot be equal to x=-2

<em>Simplify the numerator</em>

9x^{2}-36=(3x+6)(3x-6) ----> by difference of squares

substitute

f(x)=\frac{(3x+6)(3x-6)}{3x+6}

simplify

f(x)=3x-6

The domain is all real numbers except the value of x=-2

The y-intercept is the point (0,-6) ---> value of y when the value of x is equal to zero)

The x-intercept is the point (2,0) ---> value of x when the value of y is equal to zero)

therefore

The graph in the attached figure

7 0
3 years ago
Find the length of the legs of a right triangle if both legs are equal and the hypotenuse is 10?
Annette [7]

Answer:

length of the legs is 5\sqrt{2}

Step-by-step explanation:

the both sides of the  length of the legs of a right triangle are equal

So it form a isosceles triangle 45- 45- 90 degree triangle

the ratio of 45-45-90 degree triangle is x:x:x\sqrt{2}

xsqrt(2) is the side opposite to 90 degree

so hypotenuse =x\sqrt{2}

10=x\sqrt{2}

Divide both sides by square root (2)

\frac{10}{\sqrt{2}}=x

multiply square root (2) at the top and bottom

\frac{10 \cdot \sqrt{2}}{2}=x

x=5\sqrt{2}

length of the legs is 5\sqrt{2}

8 0
4 years ago
PLEASE HELP ME! ILL GIVE BRAINLIEST SHOW UR WORK
Finger [1]

Answer: x=−3 and y=13

Step-by-step explanation: y=−4x+1, 11y=x+146

11(-4x+1)=x+14y

y=-4(-3)+1

11(-4x+1)

11(-4x)+11(1)

-11(4x)=11(1)

-44x+11-11=x+146-11

-44x-x=x+135-x

-45x/-45=135/-45

x=-3

-4(-3)+1

12+1

y=13

x=−3 and y=13

8 0
3 years ago
Cramers Rule? I am confused
timofeeve [1]

D is the determinant of the coefficient matrix:

D=\begin{vmatrix}3&-1\\-3&5\end{vmatrix}=3\times5-(-1)\times(-3)=12

D_x is the determinant of the coefficient matrix, but this time you replace the x-coefficients with the values on the right hand side of the equations:

D_x=\begin{vmatrix}-1&-1\\13&5\end{vmatrix}=(-1)\times5-(-1)\times13=\boxed{8}

8 0
3 years ago
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