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2 years ago

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mmmbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

2 answers:

Iteru [2.4K]2 years ago

6 0

Answer:

mmmbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Step-by-step explanation:

yuh get into ittttt

artcher [175]2 years ago

3 0

dang im gettin hell.a points today fhfjfjfjfjfjfjfkfkfkfjfjfjfjfjfjfjfjfjffjfjfjjfjfjfjjfjfjfjfjfjfjfjfjffjjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjfjffjjfjfjfjfjfjfjfjfjjfjfjfjfjfjfjfjfjfjfjfjjfj

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2 years ago

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Step-by-step explanation:

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2 years ago

Please help me with these questions

Sindrei [870]

1) 8^-24 = 1 / 8^24
2) 6^-1 = 1/6
3) 5^-8 = 1 / 5^8
4) -3^1 = -3
5) 4^-4 = 1 / 4^4
6) 5^9
7) 8^-3 = 1 / 8^3
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6 0

2 years ago

Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2

tigry1 [53]

Answer:

$=-12$

$d(u,v)=2\sqrt{31}$

Step-by-step explanation:

We are given that inner product defined on $R_n$

$=3u_1v_1+u_2v_2$

u=(0,-4),v=(5,3)

We have to find the value of <u,v> and d(u,v)

We have $u_1=0,u_2=-4,v_1=5,v_2=3$

Substitute the value then we get

$=3(0\cdot5)+(-4)(3)=-12$

Now, $d(u,v)=\left \|v-u\right \|$

Using this formula we get

$d(u,v)=\left \| (5,7) \right \|=\sqrt{3(5)^2+(7)^2}=\sqrt{75+49}=\sqrt{124}$

$d(u,v)=2\sqrt{31}$

7 0

3 years ago

I need the answer please. Because I think i got mine wrong

Gekata [30.6K]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

• $a^{-m}$ ⇔ $\frac{1}{a^{m} }$

• $a^{0}$ = 1

• $a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

Given

(a)

$8^{-2}$ = $\frac{1}{8^{2} }$

(b)

$\frac{1}{3^{-3} }$ = 3³

(c)

$6^{-12}$ × $6^{8}$ × $6^{0}$

= $6^{(-12+8)}$ × 1

= $6^{-4}$

= $\frac{1}{6^{4} }$

7 0

3 years ago

Read 2 more answers