Answer:
The last one
Step-by-step explanation:
Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Line M with slope 6 is neither, line n with slope -6 is parallel because only lines with same slope are parallel, line p with slope 1/6 is neither. and line q with slope -1/6 is perpendicular because only the reciprocal of a slope is perpendicular, so reciprocal of 6= 1/6 reciprocal of -6=-1/6 reciprocal of 2= 1/2
Use property of proportion:
miles time (hs)
90 2.25
x 1
x = 90 ÷ 2.25
x = 40 miles
The answer is 1/4.
The genes when combined must be Heterozygous, meaning they have one dominant and one recessive, Celia must have gotten the 1/4 recessive, and it won't change the way genetics are just because you've already had offspring, the percentage stays the same.
