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2 years ago

What is the solution to -(6 m + 8) = 4(17 - m)?

Mathematics

2 answers:

icang [17]2 years ago

6 0

Answer:

m=-38

Step-by-step explanation:

oee [108]2 years ago

3 0

The answer is m 38. hope this helps

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1.17 − 0.07a + (−3.92a) What is this ????

umka21 [38]

Answer: 17-3.99a

Step-by-step explanation:

Remove parentheses.

17- 0.07a- 3.92a17−0.07a− 3.92a

Collect like terms.

17+(−0.07a−3.92a)

Simplify.

17−3.99a

7 0

2 years ago

Simplify x + 1/2 (x-5) =20

Aneli [31]

Answer: x=15

Step-by-step explanation: Let's solve your equation step-by-step.

x+ 1 /2

(x−5)=20

Step 1: Simplify both sides of the equation.

x+ 1 /2

(x−5)=20

x+( 1 /2 )(x)+( 1 /2 )(−5)=20(Distribute)

x+ 1 /2

x+ −5 /2 =20

(x+ 1 /2 x)+( −5 /2 )=20(Combine Like Terms)

3 /2 x + −5 /2 =20

Step 2: Add 5/2 to both sides.

3 /2 x + −5 /2 + 5 /2 =20+ 5 /2

3 /2 x= 45 /2

Step 3: Multiply both sides by 2/3.

( 2 /3 )*( 3 /2 x)=( 2 /3 )*( 45 /2 )

x=15

5 0

2 years ago

Round each mixed number to the nearest whole number and then estimate the product

AnnZ [28]

3 4/5 rounds to 4
5 1/6 rounds to 5
4 x 5 = 20

I hope this helped! :)

3 0

2 years ago

WHO CAN solve it Please !

Mariulka [41]

Answer:

a) True

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

Step-by-step explanation:

Step(i):-

Given that the definite integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$

we know that the trigonometric formula

sin²∝+cos²∝ = 1

cos²∝ = 1-sin²∝

step(ii):-

Now the integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$

= $\int\limits^\pi _0 {cos\alpha } \, dx$

Now, Integrating

$= ( sin\alpha )_{0} ^{\pi }$

= sin π - sin 0

= 0-0

= 0

Final answer:-

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

5 0

2 years ago

I suck at math help me please

Georgia [21]

Answer:

c negative one , negative 2

8 0

2 years ago

Read 2 more answers