The theoretical yield of BaCO3 is 5.5
<h3>What is theoretical yield?</h3>
The theoretical yield is the yield calculated from the stoichiometry of the reaction. The equation of the reaction is;
Ba(NO3)2(aq) + Na2CO3 (aq) ------> BaCO3(s) + 2NaNO3(aq)
Number of moles of limiting reactant: 0.4 M × 70/1000 = 0.028 moles
Since the reaction is 1:1,om;y 1 mole of BaCO3 is formed. Hence, mass of BaCO3 = 0.028 moles × 197 g/mol = 5.5g
Learn more about theoretical yield: brainly.com/question/2506978
The empirical formula : MnO₂.
<h3>Further explanation</h3>
Given
632mg of manganese(Mn) = 0.632 g
368mg of oxygen(O) = 0.368 g
M Mn = 55
M O = 16
Required
The empirical formula
Solution
You didn't include the pictures, but the steps for finding the empirical formula are generally the same
- Find mol(mass : atomic mass)
Mn : 0.632 : 55 = 0.0115
O : 0.368 : 16 =0.023
- Divide by the smallest mol(Mn=0.0115)
Mn : O =
The empirical formula : MnO₂
Mass = moles x Mr
So in this case the moles =1
And the Mr equals =11
So you would do - 11x1= 11grams
If you’re talking about a reaction, an increase in the products (values on the right side of the chemical equation) would cause the reaction to shift left instead of right. Also a decrease in the reactants.
Also, could be wrong, but increasing the volume/ decreasing the pressure on the reactant side will cause the reaction to shift left
1 mole of particles = 6.02*10²³
8.59 *10²³atoms*(1 mol/6.02*10²³ atoms) = (8.59/6.02) mol
M(Cl)=35.5 g/mol
(8.59/6.02) mol*35.5 g/mol=50.7 g
