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vredina [299]
2 years ago
11

WHICH ONE?????????????????? Brainlest

Chemistry
2 answers:
FromTheMoon [43]2 years ago
5 0

Answer:

I believe it would be C, The number of atoms in the reactants is equal to the number of atoms composing the products

Explanation:

hope this helps! :D

have a miraculous day!! <3

andrezito [222]2 years ago
3 0

Answer:

The number of atoms in the reactants is equal to the number of atoms composing the products

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What is the difference between potential and kinetic energy
erik [133]
Potential energy<span> is the stored </span>energy<span> in an object due of its position or its configuration where as </span>Kinetic energy<span> is the </span>energy<span> which a body possesses because of its motion.</span>
4 0
3 years ago
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Balance the following:<br> _H2SO4 + _NaNO2 → _HNO2 + _Na2SO4
Alisiya [41]

Answer:

it is balanced

Explanation:

i solved it

4 0
3 years ago
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The radioactive substance cesium-137 has a half-life of 30 years. The amount At (in grams) of a sample of cesium-137 remaining a
stealth61 [152]

<u>Answer:</u> The amount of sample left after 20 years is 288.522 g and after 50 years is 144.26 g

<u>Explanation:</u>

We are given a function that calculates the amount of sample remaining after 't' years, which is:

A_t(t)=458\times (\frac{1}{2})^{\frac{t}{30}

  • <u>For t = 20 years</u>

Putting values in above equation:

A_t(t)=458\times (\frac{1}{2})^{\frac{20}{30}

A_t(t)=288.522g

Hence, the amount of sample left after 20 years is 288.522 g

  • <u>For t = 50 years</u>

Putting values in above equation:

A_t(t)=458\times (\frac{1}{2})^{\frac{50}{30}

A_t(t)=144.26g

Hence, the amount of sample left after 50 years is 144.26 g

6 0
3 years ago
An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at
Yakvenalex [24]

Answer:

  • <u>68.3g</u>

Explanation:

<u>1. Word equation:</u>

  • <em>mercury(II) oxide → mercury + oxygen </em>

<u>2. Balanced molecular equation:</u>

  • 2HgO → 2Hg + O₂(g)

<u>3. Mole ratio</u>

Write the ratio of the coefficients of the substances that are object of the problem:

       2molHgO/1molO_2

<u>4. Calculate the number of moles of O₂(g)</u>

Use the equation for ideal gases:

          pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol

<u>5. Calculate the number of moles of HgO</u>

         \dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO

<u>6. Convert to mass</u>

  • mass = # moles × molar mass

  • molar mass of HgO: 216.591g/mol

  • mass = 0.315mol × 216.591g/mol = 68.3g

7 0
3 years ago
A sample of aluminum weighs 100 grams and has a volume of 37.03 cm. What is the density of
Alexxandr [17]

Answer:

2.7005 g/cm²

explanation: as we know density=mass/volume

6 0
3 years ago
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