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2 years ago

WHICH ONE?????????????????? Brainlest

Chemistry

2 answers:

FromTheMoon [43]2 years ago

5 0

Answer:

I believe it would be C, The number of atoms in the reactants is equal to the number of atoms composing the products

Explanation:

hope this helps! :D

have a miraculous day!! <3

andrezito [222]2 years ago

3 0

Answer:

The number of atoms in the reactants is equal to the number of atoms composing the products

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3 years ago

Seawater is around a 3% aqueous salt solution.

Eduardwww [97]

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2 years ago

How many moles are in 100g of carbon dioxide?

Fantom [35]

Answer:

Explanation:

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3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

Citrus2011 [14]

Answer: The mass of lead iodide produced is 9.22 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

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3 years ago

What is a chemical bond?

hodyreva [135]

A chemical bond is lasting attraction between atoms that enables the formation of chemical compounds.

8 0

3 years ago

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