All categories

2 years ago

WHICH ONE?????????????????? Brainlest

Chemistry

2 answers:

FromTheMoon [43]2 years ago

5 0

Answer:

I believe it would be C, The number of atoms in the reactants is equal to the number of atoms composing the products

Explanation:

hope this helps! :D

have a miraculous day!! <3

andrezito [222]2 years ago

3 0

Answer:

The number of atoms in the reactants is equal to the number of atoms composing the products

You might be interested in

If an atom has 6 valence electrons, how many electrons does it need to gain to achieve a stable electron configuration?

shusha [124]

it would need to gain 2 more for it to achieve a stable configuration

the best way to remember this is the noble gasses all have 8 valence electrons and that they are the most stable elements on the periodic table

4 0

3 years ago

Read 2 more answers

A theater director reinterprets a play by replacing its classical score with

cricket20 [7]

Answer:

The play will be more appealing to a younger audience.

Explanation:

A younger audience will more likely appreciate current pop hits rather than classical score.

4 0

3 years ago

Read 2 more answers

What is the density of a block of marble that occupies 277 cm3 and has a mass of 928 g? Answer in units of g/cm3 .

Evgesh-ka [11]

$V=277cm^{3}\\
m=928g\\\\
d=\frac{m}{V}=\frac{928g}{277cm^{3}}\approx3,35\frac{g}{cm^{3}}$

8 0

3 years ago

Consider the second-order reaction:

kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

Explanation:

$2HI(g)\rightarrow H_2(g)+I_2(g)
$

Rate Law: $k[HI]^2
$

Rate constant of the reaction = k = $6.4\times 10^{-9} L/mol s$

Order of the reaction = 2

Initial rate of reaction = $R=1.6\times 10^{-7} Mol/L s$

Initial concentration of HI = $[A_o]$

$1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2$

$[A_o]=5 mol/L$

Final concentration of HI after t = [A]

t = $4.53\times 10^{10} s$

Integrated rate law for second order kinetics is given by:

$\frac{1}{[A]}=kt+\frac{1}{[A_o]}$

$\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}$

$[A]=0.00345 mol/L$

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

5 0

3 years ago

There are two isotopes of chlorine. below is a list of each and their mass and abundance. calculate the atomic mass of chlorine.

Vesna [10]

Chlorine is very lequid structure

6 0

3 years ago