Divide 60 g with the molar mass and you have 1.0265 moles
Explanation:
The given data is as follows.
Initial concentration = 0.15 mg/ml,
Final concentration = 0.1 mg/ml, (as )
Final volume = = 0.1 ml
According to the dilution formula we get the following.
or, =
Putting the given values into the above formula we get the following.
=
=
= 0.0667 ml
=
= 66.7 microliter
This means that volume of protein stock which is required is 66.7 ml. Hence, calculate the volume of water required as follows.
Volume of water required = Total volume - volume of protein stock
= (100 - 66.7) microliter
= 33.3 microliter
Thus, we can conclude that we need 33.3 microliter of water and 66.7 microliter of protein.
Percentage by mass of water in CuSO4.5H20 is 36.07% .
In this problem we have - copper(II) sulfate pentahydrate and it's molecular formula is (CuSO₄.5H₂O) .
There are 5 molecules of water are present.
Now we calculate it's molar mass-
We know that-
molar mass of Cu = 63.5u
Molar mass of SO₄ = 96 u
Molar mass of H₂O = 18 u
Now, molar mass of (CuSO₄.5H₂O) = 63.5 + 96 + 5 × 18
Now, molar mass of (CuSO₄.5H₂O) = 249.5u
And mass of water in CuSO₄.5H₂O = 90 u
now mass percentage of water = mass of water ÷ Total mass ×100
now mass percentage of water = 90 ÷ 249.5 × 100
now mass percentage of water = 36.07 %
So we find out mass percent by dividing given mass with total mass and then multiplying it with hundred and it came out to be 36.07 % .
Learn more about mass percent here: brainly.com/question/13896694
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