If you begin with the basic equation of a vertical parabola: y-k=a(x-h)^2, where (h,k) is the vertex, then that equation, when the vertex is (-3,-2), is
y + 2 = a (x + 3)^2. If we solve this for y, we get
y = a(x+3)^2 - 2. Thus, eliminate answers A and D. That leaves B, since B correctly shows (x+3)^2.
6/40 is equalvilant because all you have to do is double or simplify it by 2
"An angle that forms a linear pair with one of the interior angle the triangle" is the best definition of an exterior angle of a triangle.
<u>Option: C</u>
<u>Explanation:</u>
When to the sum of the inward angles opposite outer angle of a triangle the sum of the inward angles opposite is equivalent thus understood as exterior angle of a triangle.
The Triangle outer angle theorem for more about is if at each vertex the equivalent angle is drawn, the outer angles always add up to 360°. In reality, this is valid for any convex polygon, not just triangles.
In the most easiest pattern , since any angle of triangle equivalent is 60′, the outer angle would be 120′. Therefore all exterior angles sum is:
120 + 120 + 120 = 360°.
Answer:
y = 3x -2
Step-by-step explanation:
If the line is parallel, that means it has the same slope. The given equation had a slope of 3, so the new line must also have a slope of 3.
You can plug the given coordinates into the slope-intercept form with a slope of 3 to find your answer.
y = m*x + b
7 = 3*3 + b
7 = 9 + b
-2 = b
y = 3x -2
Answer:
The answer to the question is C
